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(8) Find the differential for the function using logarithmic differentiation. y = (sin x) (sec); (A) Iny = sec r In (sin r) and so dyy'dr = (sin x)(secz)[ [sec r tan r In (sin r) + csc r) dr (B) In y sec r In (sin x) and so dy = y'dx = (sin x)(secr). secrtan z In (sin x) csc r dr (C) y = (sin x) sec dy = y'dr = (sin x) (sec z 1). dr z and so (D) y = (sin x) sec z and so dy = y'dx = (sin x) (secr-1).secx tan x da

(8) Find the differential for the function using logarithmic differentiation. y = (sin x) (sec); (A) Iny = sec r In (sin r) and so dyy'dr = (sin x)(secz)[ [sec r tan r In (sin r) + csc r) dr (B) In y sec r In (sin x) and so dy = y'dx = (sin x)(secr). secrtan z In (sin x) csc r dr (C) y = (sin x) sec dy = y'dr = (sin x) (sec z 1). dr z and so (D) y = (sin x) sec z and so dy = y'dx = (sin x) (secr-1).secx tan x da

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2 (A) In y = sec r. In (sin x) (B) In y = sec x. ln (sin x) (C) y I = (sin x) sec (D) y = (sin x) sec r and so and so and so and so (8) Find the differential for the function using logarithmic differentiation. y = (sin x) (secr): dy = y'dx = (sin x) (sec ) [sec z tan r ln (sin r) + csc r). dr dy = y'dx = (sin x) (sec). sec z tanz. In (sin x). csc x. dr dy = y'dx = (sin x) (secx-1). dx dy = y'dx = (sin x) (secr-1). sec z tan x dr
Transcribed Image Text:2 (A) In y = sec r. In (sin x) (B) In y = sec x. ln (sin x) (C) y I = (sin x) sec (D) y = (sin x) sec r and so and so and so and so (8) Find the differential for the function using logarithmic differentiation. y = (sin x) (secr): dy = y'dx = (sin x) (sec ) [sec z tan r ln (sin r) + csc r). dr dy = y'dx = (sin x) (sec). sec z tanz. In (sin x). csc x. dr dy = y'dx = (sin x) (secx-1). dx dy = y'dx = (sin x) (secr-1). sec z tan x dr
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