8 Explain why the form 1 is indeterminate and cannot be evaluated by substitution. Explain how the competing functions behave. Choose the correct answer. OA. If lim f(x)=1 and lim g(x)=co, then f(x)9(x)1 as xa, which is meaningless. Therefore, substitution cannot be used. xa x-a OB. If lim f(x)=1 and lim g(x)=co, then f(x)9(x) as xa, so the limit does not exist. Therefore, substitution cannot be used. x-a xa OC. If lim f(x)=1 and lim g(x) = oo, then f(x)oo as x-a, so the limit does not exist. Therefore, substitution cannot be used. x-a x-a D. If lim f(x)=1 and lim g(x) co, then f(x)9(x)0° as x-a which is meaningless. Therefore, substitution cannot be used. x-a х-а

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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8
Explain why the form 1 is indeterminate and cannot be evaluated by substitution. Explain how the competing functions behave.
Choose the correct answer.
OA. If lim f(x)=1 and lim g(x)=co, then f(x)9(x)1 as xa, which is meaningless. Therefore, substitution cannot be used.
xa
x-a
OB. If lim f(x)=1 and lim g(x)=co, then f(x)9(x) as xa, so the limit does not exist. Therefore, substitution cannot be used.
x-a
xa
OC. If lim f(x)=1 and lim g(x) = oo, then f(x)oo as x-a, so the limit does not exist. Therefore, substitution cannot be used.
x-a
x-a
D. If lim f(x)=1 and lim g(x) co, then f(x)9(x)0° as x-a which is meaningless. Therefore, substitution cannot be used.
x-a
х-а
Transcribed Image Text:8 Explain why the form 1 is indeterminate and cannot be evaluated by substitution. Explain how the competing functions behave. Choose the correct answer. OA. If lim f(x)=1 and lim g(x)=co, then f(x)9(x)1 as xa, which is meaningless. Therefore, substitution cannot be used. xa x-a OB. If lim f(x)=1 and lim g(x)=co, then f(x)9(x) as xa, so the limit does not exist. Therefore, substitution cannot be used. x-a xa OC. If lim f(x)=1 and lim g(x) = oo, then f(x)oo as x-a, so the limit does not exist. Therefore, substitution cannot be used. x-a x-a D. If lim f(x)=1 and lim g(x) co, then f(x)9(x)0° as x-a which is meaningless. Therefore, substitution cannot be used. x-a х-а
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