8 A rectangulaer garden with an area of 30m is Surrounded by a grass border Im wide on two Sides and am on tle other Side. what dimensions of the gerdon minimize the combined area of the garden and borders ?

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.4: Graphing Polynomial Functions
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**Problem 8: Minimizing the Combined Area of a Garden and Borders**

A rectangular garden with an area of \(30 \, \text{m}^2\) is surrounded by a grass border. The grass border is 1 meter wide on two sides and 2 meters wide on the other two sides.

**Question:** What dimensions of the garden minimize the combined area of the garden and the borders?

This problem involves optimization, a common topic in calculus and geometry. The goal is to find the dimensions of the rectangular garden (length and width) that will minimize the total area, which includes both the garden and the surrounding grass borders.

### Explanation:

- Let the dimensions of the garden be \( l \times w \) where \( l \) is the length and \( w \) is the width.
- The area of the garden is given: \( l \times w = 30 \, \text{m}^2 \).

Surrounding this garden is a grass border:
- On two sides, the width of the border is 1 meter.
- On the other two sides, the width is 2 meters.

To define the total area (garden + borders):
- The total length considering the borders would be \( l + 2 \times 2 = l + 4 \) meters.
- The total width considering the borders would be \( w + 1 + 1 = w + 2 \) meters.

Thus, the combined area \(A_{total}\) is:
\[ A_{total} = (l + 4)(w + 2) \]

Given the area of the garden (\( l \times w = 30 \)), we can set up the equation to minimize:
\[ A_{total} = (l + 4)(\frac{30}{l} + 2) \]

The task then involves differentiating this equation with respect to \( l \) and finding the value of \( l \) that minimizes \( A_{total} \). We then use this \( l \) to find the corresponding \( w \) that satisfies \( l \times w = 30 \).

This kind of problem is frequently solved using techniques from calculus, such as finding the derivative, setting it to zero, and solving for the critical points.
Transcribed Image Text:**Problem 8: Minimizing the Combined Area of a Garden and Borders** A rectangular garden with an area of \(30 \, \text{m}^2\) is surrounded by a grass border. The grass border is 1 meter wide on two sides and 2 meters wide on the other two sides. **Question:** What dimensions of the garden minimize the combined area of the garden and the borders? This problem involves optimization, a common topic in calculus and geometry. The goal is to find the dimensions of the rectangular garden (length and width) that will minimize the total area, which includes both the garden and the surrounding grass borders. ### Explanation: - Let the dimensions of the garden be \( l \times w \) where \( l \) is the length and \( w \) is the width. - The area of the garden is given: \( l \times w = 30 \, \text{m}^2 \). Surrounding this garden is a grass border: - On two sides, the width of the border is 1 meter. - On the other two sides, the width is 2 meters. To define the total area (garden + borders): - The total length considering the borders would be \( l + 2 \times 2 = l + 4 \) meters. - The total width considering the borders would be \( w + 1 + 1 = w + 2 \) meters. Thus, the combined area \(A_{total}\) is: \[ A_{total} = (l + 4)(w + 2) \] Given the area of the garden (\( l \times w = 30 \)), we can set up the equation to minimize: \[ A_{total} = (l + 4)(\frac{30}{l} + 2) \] The task then involves differentiating this equation with respect to \( l \) and finding the value of \( l \) that minimizes \( A_{total} \). We then use this \( l \) to find the corresponding \( w \) that satisfies \( l \times w = 30 \). This kind of problem is frequently solved using techniques from calculus, such as finding the derivative, setting it to zero, and solving for the critical points.
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