8 -50 -100 G5 = to the corresponding Bode plots in Figure 0 -90 -180 10 Pair the transfer functions 10 Bode plot A 10° Frequency (rad/s) G₁ = 10 G3 = 8 (s+1)(s+2) 1 (s+1)(8+2) 8-1 (s+1)(8+2) -100 0 -90 -180 10 G₂ = G₁ = G6= Bode plot B 10⁰ Frequency (rad/s) 10 1 s-1 1 s(s+1) 1 82 +8+1.25 10² -20 -180 10:0 -20 -40 180 0 -180 10 10 Bode plot C 10⁰ Frequency (rad/s) Bode plot E 10' 10⁰ Frequency (rad/s) 10 102 102 -50 -100 90 -90 10€ 100 0 -100 -90 -180 100 101 Bode plot D 10⁰ Frequency (rad/s) 10:1 Bode plot F 10° Frequency (rad/s) 101 10" 10²
8 -50 -100 G5 = to the corresponding Bode plots in Figure 0 -90 -180 10 Pair the transfer functions 10 Bode plot A 10° Frequency (rad/s) G₁ = 10 G3 = 8 (s+1)(s+2) 1 (s+1)(8+2) 8-1 (s+1)(8+2) -100 0 -90 -180 10 G₂ = G₁ = G6= Bode plot B 10⁰ Frequency (rad/s) 10 1 s-1 1 s(s+1) 1 82 +8+1.25 10² -20 -180 10:0 -20 -40 180 0 -180 10 10 Bode plot C 10⁰ Frequency (rad/s) Bode plot E 10' 10⁰ Frequency (rad/s) 10 102 102 -50 -100 90 -90 10€ 100 0 -100 -90 -180 100 101 Bode plot D 10⁰ Frequency (rad/s) 10:1 Bode plot F 10° Frequency (rad/s) 101 10" 10²
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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