[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the volume proportion of solid copper in a sample, was given by J 6y1(1 – y1) 0< y1 < 1 f1(y1) = elsewhere The density function for Y2, the proportion of type A crystals among the solid copper, was given as (3y 0< y2 <1 f2(४2) = elsewhere The variable U = YY2 gives the proportion of the sample volume due to type A crystals. If Yi and Y, are independent, find the probability density function for U.
[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the volume proportion of solid copper in a sample, was given by J 6y1(1 – y1) 0< y1 < 1 f1(y1) = elsewhere The density function for Y2, the proportion of type A crystals among the solid copper, was given as (3y 0< y2 <1 f2(४2) = elsewhere The variable U = YY2 gives the proportion of the sample volume due to type A crystals. If Yi and Y, are independent, find the probability density function for U.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the
volume proportion of solid copper in a sample, was given by
6y1(1 – yı) 0 < y1 <1
f1(y1) =
elsewhere
The density function for Y2, the proportion of type A crystals among the solid copper, was
given as
|3y3 0< y2 < 1
f2(y2) =
0.
elsewhere
The variable U = Y¡Y2 gives the proportion of the sample volume due to type A crystals. If
Y and Y, are independent, find the probability density function for U.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fff56f00f-4be7-4511-bc7b-9683d0cff601%2F44f921cc-51e3-42a1-a452-e0ce3a767b28%2Fqspnko_processed.jpeg&w=3840&q=75)
Transcribed Image Text:[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the
volume proportion of solid copper in a sample, was given by
6y1(1 – yı) 0 < y1 <1
f1(y1) =
elsewhere
The density function for Y2, the proportion of type A crystals among the solid copper, was
given as
|3y3 0< y2 < 1
f2(y2) =
0.
elsewhere
The variable U = Y¡Y2 gives the proportion of the sample volume due to type A crystals. If
Y and Y, are independent, find the probability density function for U.
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