8 2 f(x)dx -43, then | f(t)dt = If 8.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
The image contains a mathematical statement involving definite integrals. The statement reads:

"If 
\[ \int_{2}^{8} f(x) \, dx = -43, \]
then 
\[ \int_{8}^{2} f(t) \, dt = \]"

To provide some context for educational purposes, we can add an explanation:

### Explanation:
A definite integral of a function \( f(x) \) over the interval \([a, b]\) is represented as \( \int_{a}^{b} f(x) \, dx \). This integral calculates the net area under the curve of \( f(x) \) between \( x = a \) and \( x = b \).

In this problem, we are given that the definite integral of \( f(x) \) from \( x = 2 \) to \( x = 8 \) is \(-43\):

\[ \int_{2}^{8} f(x) \, dx = -43. \]

We need to find the value of the definite integral of \( f(t) \) from \( t = 8 \) to \( t = 2 \):

\[ \int_{8}^{2} f(t) \, dt. \]

To compute this, we use the property of definite integrals that states reversing the limits of integration changes the sign of the integral:

\[ \int_{a}^{b} f(x) \, dx = -\int_{b}^{a} f(x) \, dx. \]

Applying this property:

\[ \int_{8}^{2} f(t) \, dt = -\int_{2}^{8} f(t) \, dt. \]

Given that \( \int_{2}^{8} f(x) \, dx = -43 \),

\[ \int_{8}^{2} f(t) \, dt = -(-43) = 43. \]

Therefore, the answer is:

\[ \int_{8}^{2} f(t) \, dt = 43. \]
Transcribed Image Text:The image contains a mathematical statement involving definite integrals. The statement reads: "If \[ \int_{2}^{8} f(x) \, dx = -43, \] then \[ \int_{8}^{2} f(t) \, dt = \]" To provide some context for educational purposes, we can add an explanation: ### Explanation: A definite integral of a function \( f(x) \) over the interval \([a, b]\) is represented as \( \int_{a}^{b} f(x) \, dx \). This integral calculates the net area under the curve of \( f(x) \) between \( x = a \) and \( x = b \). In this problem, we are given that the definite integral of \( f(x) \) from \( x = 2 \) to \( x = 8 \) is \(-43\): \[ \int_{2}^{8} f(x) \, dx = -43. \] We need to find the value of the definite integral of \( f(t) \) from \( t = 8 \) to \( t = 2 \): \[ \int_{8}^{2} f(t) \, dt. \] To compute this, we use the property of definite integrals that states reversing the limits of integration changes the sign of the integral: \[ \int_{a}^{b} f(x) \, dx = -\int_{b}^{a} f(x) \, dx. \] Applying this property: \[ \int_{8}^{2} f(t) \, dt = -\int_{2}^{8} f(t) \, dt. \] Given that \( \int_{2}^{8} f(x) \, dx = -43 \), \[ \int_{8}^{2} f(t) \, dt = -(-43) = 43. \] Therefore, the answer is: \[ \int_{8}^{2} f(t) \, dt = 43. \]
Expert Solution
Step 1

Given

Calculus homework question answer, step 1, image 1

By the property of definite integral, we have

Calculus homework question answer, step 1, image 2

Step 2

Therefore, we have

Calculus homework question answer, step 2, image 1

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