Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![The image contains a mathematical statement involving definite integrals. The statement reads:
"If
\[ \int_{2}^{8} f(x) \, dx = -43, \]
then
\[ \int_{8}^{2} f(t) \, dt = \]"
To provide some context for educational purposes, we can add an explanation:
### Explanation:
A definite integral of a function \( f(x) \) over the interval \([a, b]\) is represented as \( \int_{a}^{b} f(x) \, dx \). This integral calculates the net area under the curve of \( f(x) \) between \( x = a \) and \( x = b \).
In this problem, we are given that the definite integral of \( f(x) \) from \( x = 2 \) to \( x = 8 \) is \(-43\):
\[ \int_{2}^{8} f(x) \, dx = -43. \]
We need to find the value of the definite integral of \( f(t) \) from \( t = 8 \) to \( t = 2 \):
\[ \int_{8}^{2} f(t) \, dt. \]
To compute this, we use the property of definite integrals that states reversing the limits of integration changes the sign of the integral:
\[ \int_{a}^{b} f(x) \, dx = -\int_{b}^{a} f(x) \, dx. \]
Applying this property:
\[ \int_{8}^{2} f(t) \, dt = -\int_{2}^{8} f(t) \, dt. \]
Given that \( \int_{2}^{8} f(x) \, dx = -43 \),
\[ \int_{8}^{2} f(t) \, dt = -(-43) = 43. \]
Therefore, the answer is:
\[ \int_{8}^{2} f(t) \, dt = 43. \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F139cb5f2-923a-4627-93ad-b9a40e985e19%2F437676f1-77b4-4c96-94ca-8f68629a5076%2Fzql8s8s.png&w=3840&q=75)
Transcribed Image Text:The image contains a mathematical statement involving definite integrals. The statement reads:
"If
\[ \int_{2}^{8} f(x) \, dx = -43, \]
then
\[ \int_{8}^{2} f(t) \, dt = \]"
To provide some context for educational purposes, we can add an explanation:
### Explanation:
A definite integral of a function \( f(x) \) over the interval \([a, b]\) is represented as \( \int_{a}^{b} f(x) \, dx \). This integral calculates the net area under the curve of \( f(x) \) between \( x = a \) and \( x = b \).
In this problem, we are given that the definite integral of \( f(x) \) from \( x = 2 \) to \( x = 8 \) is \(-43\):
\[ \int_{2}^{8} f(x) \, dx = -43. \]
We need to find the value of the definite integral of \( f(t) \) from \( t = 8 \) to \( t = 2 \):
\[ \int_{8}^{2} f(t) \, dt. \]
To compute this, we use the property of definite integrals that states reversing the limits of integration changes the sign of the integral:
\[ \int_{a}^{b} f(x) \, dx = -\int_{b}^{a} f(x) \, dx. \]
Applying this property:
\[ \int_{8}^{2} f(t) \, dt = -\int_{2}^{8} f(t) \, dt. \]
Given that \( \int_{2}^{8} f(x) \, dx = -43 \),
\[ \int_{8}^{2} f(t) \, dt = -(-43) = 43. \]
Therefore, the answer is:
\[ \int_{8}^{2} f(t) \, dt = 43. \]
Expert Solution
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Step 1
Given
By the property of definite integral, we have
Step 2
Therefore, we have
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