8 16 3 Find a basis for the row space of a matrix 8 24 8 88-2

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Determinants
Section3.CM: Cumulative Review
Problem 17CM: Find the sequence of the elementary matrices whose product is the non singular matrix below. [2410]
Question
**Problem Statement:**

Find a basis for the row space of the matrix 

\[
\begin{bmatrix}
8 & 16 & 3 \\
8 & 24 & 8 \\
8 & 8 & -2
\end{bmatrix}
\]

**Answer Choices:**

1. \(\left\{ \begin{pmatrix} 2, 0, -\frac{7}{4} \end{pmatrix}, \begin{pmatrix} 0, 2, \frac{5}{4} \end{pmatrix} \right\}\)

2. \(\left\{ \begin{pmatrix} 2, 0, \frac{7}{4} \end{pmatrix}, \begin{pmatrix} 0, 2, \frac{5}{4} \end{pmatrix}, \begin{pmatrix} 0, 6, \frac{15}{4} \end{pmatrix} \right\}\)

3. \(\left\{ \begin{pmatrix} 0, 2, \frac{5}{4} \end{pmatrix}, \begin{pmatrix} 0, 6, \frac{15}{4} \end{pmatrix} \right\}\)

4. \(\left\{ \begin{pmatrix} 2, 0, \frac{7}{4} \end{pmatrix}, \begin{pmatrix} 6, 0, \frac{21}{4} \end{pmatrix} \right\}\)

5. \(\left\{ \begin{pmatrix} 2, 0, \frac{7}{4} \end{pmatrix}, \begin{pmatrix} 0, 2, \frac{5}{4} \end{pmatrix}, \begin{pmatrix} 6, 0, \frac{21}{4} \end{pmatrix} \right\}\)
Transcribed Image Text:**Problem Statement:** Find a basis for the row space of the matrix \[ \begin{bmatrix} 8 & 16 & 3 \\ 8 & 24 & 8 \\ 8 & 8 & -2 \end{bmatrix} \] **Answer Choices:** 1. \(\left\{ \begin{pmatrix} 2, 0, -\frac{7}{4} \end{pmatrix}, \begin{pmatrix} 0, 2, \frac{5}{4} \end{pmatrix} \right\}\) 2. \(\left\{ \begin{pmatrix} 2, 0, \frac{7}{4} \end{pmatrix}, \begin{pmatrix} 0, 2, \frac{5}{4} \end{pmatrix}, \begin{pmatrix} 0, 6, \frac{15}{4} \end{pmatrix} \right\}\) 3. \(\left\{ \begin{pmatrix} 0, 2, \frac{5}{4} \end{pmatrix}, \begin{pmatrix} 0, 6, \frac{15}{4} \end{pmatrix} \right\}\) 4. \(\left\{ \begin{pmatrix} 2, 0, \frac{7}{4} \end{pmatrix}, \begin{pmatrix} 6, 0, \frac{21}{4} \end{pmatrix} \right\}\) 5. \(\left\{ \begin{pmatrix} 2, 0, \frac{7}{4} \end{pmatrix}, \begin{pmatrix} 0, 2, \frac{5}{4} \end{pmatrix}, \begin{pmatrix} 6, 0, \frac{21}{4} \end{pmatrix} \right\}\)
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