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8 (1) Find the center of the conic section r = 2-cos(0) (a) (8/3,0) (b) (-8/3,0) (c) (0,8/3) (d)(0, -8/3)

8 (1) Find the center of the conic section r = 2-cos(0) (a) (8/3,0) (b) (-8/3,0) (c) (0,8/3) (d)(0, -8/3)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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8 (1) Find the center of the conic section r = 2-cos(0) (a) (8/3,0) (b) (-8/3,0) (c) (0,8/3) (d)(0, -8/3) 8 (2) Find the vertex of the conic section r = 2-cos(0) (a) (0, -8/3) (b) (8/3,0) (c) (0,8/3) (d) (-8/3,0) 8 (3) Find the focus of the conic section r = 2-cos(0) (a) (-16/3,0) (b) (16/3,0) (c) (0,16/3) (d)(0,–16/3) 8 (4) Find the directrix of the conic section r = 2-cos(0) (a) x = 40/3 (b) x = -40/3 (c) y = 40/3 (d) y = -40/3
Transcribed Image Text:8 (1) Find the center of the conic section r = 2-cos(0) (a) (8/3,0) (b) (-8/3,0) (c) (0,8/3) (d)(0, -8/3) 8 (2) Find the vertex of the conic section r = 2-cos(0) (a) (0, -8/3) (b) (8/3,0) (c) (0,8/3) (d) (-8/3,0) 8 (3) Find the focus of the conic section r = 2-cos(0) (a) (-16/3,0) (b) (16/3,0) (c) (0,16/3) (d)(0,–16/3) 8 (4) Find the directrix of the conic section r = 2-cos(0) (a) x = 40/3 (b) x = -40/3 (c) y = 40/3 (d) y = -40/3
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