7:£V I1 0 i 4ll zain 1Q K/s Homework 2.pdf > Homework 2 dy +y cotx = cosx is ... dx Q.). Solution of the differential equation sin a) y cosx = + c b) ysinx = cosx +C c) ysinx = sin*x d) ycosx = - dy 2y(1) = 1 is Q2) Particular solution of the differential equation a) x = y log|x| + y b) y = y log|x + 2x c) x = x loglyl + y d) y = x log|x| + x Q) Solution of the differential equation +2 = y? x is a) = -x +c b) == -x + c c) =-y +c (xy) d) -= -x² + c Q.) Solve the equation y" – 6y' + 13y = 0 Qs) Solve y" - y = e2x Qe) y" + 3y' + 2y = e – 3 Q2) Solve the following equation using variation of parameters methods y" - 5y' + 6y = x²e3*

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Homework 2.pdf
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Homework 2
Q.), Solution of the differential equation
dy
+y cotx = Cosx is .
sin?x
a) y cosx = +c
b) ysinx =
sin a
+c
cos x
c) ysinx =
sin x
+c
d) ycosx = -
Q2) Particular solution of the differential equation = , y(1) = 1 is
x+y
%3D
dx
a) x = y log|x| + y
b) y = y log|x| + 2x
c) x = x log|yl + y
d) y = x log|x| + x
Q3) Solution of the differential equation 2+2 = y2 x is
dx
a) = -x +c
b) -= -x+c
c) =-y +c
d) 1= -x2 + c
Q4) Solve the equation y" – 6y' + 13y = 0
Qs) Solve y" - y = e2x
Q6) y" + 3y' + 2y = e* – 3
Q2) Solve the following equation using variation of parameters methods
y" – 5y' + 6y = x²e3x
Transcribed Image Text:46,ll zain 1Q K/s Homework 2.pdf -> Homework 2 Q.), Solution of the differential equation dy +y cotx = Cosx is . sin?x a) y cosx = +c b) ysinx = sin a +c cos x c) ysinx = sin x +c d) ycosx = - Q2) Particular solution of the differential equation = , y(1) = 1 is x+y %3D dx a) x = y log|x| + y b) y = y log|x| + 2x c) x = x log|yl + y d) y = x log|x| + x Q3) Solution of the differential equation 2+2 = y2 x is dx a) = -x +c b) -= -x+c c) =-y +c d) 1= -x2 + c Q4) Solve the equation y" – 6y' + 13y = 0 Qs) Solve y" - y = e2x Q6) y" + 3y' + 2y = e* – 3 Q2) Solve the following equation using variation of parameters methods y" – 5y' + 6y = x²e3x
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