7J8P3JH-IQ1HXBxM9hozYUzCiw4JIKPX Solve the equation. Write your answers in exact, simplified form. Sd²(d²+4)=96+6d²

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.2: Adding And Subtracting Polynomials
Problem 11P
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Where did the +14d to the power of 2 go?
-1
MCC Connect Math
Explanation
awu.connectmath.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQ1HXBXM9hozYUzCiw4JIKPXwid PMfFrdm... A
Solve the equation. Write your answers in exact, simplified form.
Sd²(d²+4)=96+6d²
Apply the distributive property.
Set one side equal to zero.
Factor.
Set each factor equal to zero.
d² =
Sd²-16=0 or d²+6=0
16
d = ± √√5
Try Another
= +
(5d²-16) (d²+6) = 0
X
Sd²(a²+4)= 96+6d²
5d²+14d²-96 = 0
Both equations are quadratic equations. Write both equations in the form d2=k. Apply the square root property.
Sd²-16 = 0
5d² = 16
16
5
2
H
= ±
5d +20d² = 96+6d²2
O Search
4√5
or
or
The solutions all check in the original equation.
McGraw-Hill Connect Math
or
Thus, the solution set is
is { +4√5, ±1/√6).
or
d²+6=0
d² = -6
d = ± √-6
d = ±1√6
hp
H
X
Save For Later
+
Submit Assignment
W
B
d
Transcribed Image Text:-1 MCC Connect Math Explanation awu.connectmath.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQ1HXBXM9hozYUzCiw4JIKPXwid PMfFrdm... A Solve the equation. Write your answers in exact, simplified form. Sd²(d²+4)=96+6d² Apply the distributive property. Set one side equal to zero. Factor. Set each factor equal to zero. d² = Sd²-16=0 or d²+6=0 16 d = ± √√5 Try Another = + (5d²-16) (d²+6) = 0 X Sd²(a²+4)= 96+6d² 5d²+14d²-96 = 0 Both equations are quadratic equations. Write both equations in the form d2=k. Apply the square root property. Sd²-16 = 0 5d² = 16 16 5 2 H = ± 5d +20d² = 96+6d²2 O Search 4√5 or or The solutions all check in the original equation. McGraw-Hill Connect Math or Thus, the solution set is is { +4√5, ±1/√6). or d²+6=0 d² = -6 d = ± √-6 d = ±1√6 hp H X Save For Later + Submit Assignment W B d
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