Where did the +14d to the power of 2 go? -1MCC Connect MathExplanationawu.connectmath.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQ1HXBXM9hozYUzCiw4JIKPXwid PMfFrdm... ASolve the equation. Write your answers in exact, simplified form.Sd²(d²+4)=96+6d²Apply the distributive property.Set one side equal to zero.Factor.Set each factor equal to zero.d² =Sd²-16=0 or d²+6=016d = ± √√5Try Another= +(5d²-16) (d²+6) = 0XSd²(a²+4)= 96+6d²5d²+14d²-96 = 0Both equations are quadratic equations. Write both equations in the form d2=k. Apply the square root property.Sd²-16 = 05d² = 161652H= ±5d +20d² = 96+6d²2O Search4√5ororThe solutions all check in the original equation.McGraw-Hill Connect MathorThus, the solution set isis { +4√5, ±1/√6).ord²+6=0d² = -6d = ± √-6d = ±1√6hpHXSave For Later+Submit AssignmentWBd

Answered: Image /qna-images/answer/9f312f5a-dcaf-4db3-a2d5-5cf046acb367.jpg

Answered: 7J8P3JH-IQ1HXBxM9hozYUzCiw4JIKPX Solve…

7J8P3JH-IQ1HXBxM9hozYUzCiw4JIKPX Solve the equation. Write your answers in exact, simplified form. Sd²(d²+4)=96+6d²

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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