Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.2: Adding And Subtracting Polynomials
Problem 11P
Related questions
Question
100%
Where did the +14d to the power of 2 go?
![-1
MCC Connect Math
Explanation
awu.connectmath.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQ1HXBXM9hozYUzCiw4JIKPXwid PMfFrdm... A
Solve the equation. Write your answers in exact, simplified form.
Sd²(d²+4)=96+6d²
Apply the distributive property.
Set one side equal to zero.
Factor.
Set each factor equal to zero.
d² =
Sd²-16=0 or d²+6=0
16
d = ± √√5
Try Another
= +
(5d²-16) (d²+6) = 0
X
Sd²(a²+4)= 96+6d²
5d²+14d²-96 = 0
Both equations are quadratic equations. Write both equations in the form d2=k. Apply the square root property.
Sd²-16 = 0
5d² = 16
16
5
2
H
= ±
5d +20d² = 96+6d²2
O Search
4√5
or
or
The solutions all check in the original equation.
McGraw-Hill Connect Math
or
Thus, the solution set is
is { +4√5, ±1/√6).
or
d²+6=0
d² = -6
d = ± √-6
d = ±1√6
hp
H
X
Save For Later
+
Submit Assignment
W
B
d](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff8411dad-f4bd-4852-a80d-7160671c8489%2F9f312f5a-dcaf-4db3-a2d5-5cf046acb367%2Fhd38orh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:-1
MCC Connect Math
Explanation
awu.connectmath.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQ1HXBXM9hozYUzCiw4JIKPXwid PMfFrdm... A
Solve the equation. Write your answers in exact, simplified form.
Sd²(d²+4)=96+6d²
Apply the distributive property.
Set one side equal to zero.
Factor.
Set each factor equal to zero.
d² =
Sd²-16=0 or d²+6=0
16
d = ± √√5
Try Another
= +
(5d²-16) (d²+6) = 0
X
Sd²(a²+4)= 96+6d²
5d²+14d²-96 = 0
Both equations are quadratic equations. Write both equations in the form d2=k. Apply the square root property.
Sd²-16 = 0
5d² = 16
16
5
2
H
= ±
5d +20d² = 96+6d²2
O Search
4√5
or
or
The solutions all check in the original equation.
McGraw-Hill Connect Math
or
Thus, the solution set is
is { +4√5, ±1/√6).
or
d²+6=0
d² = -6
d = ± √-6
d = ±1√6
hp
H
X
Save For Later
+
Submit Assignment
W
B
d
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