7cm 40cm ر NOT TO SCALE FINDING EJ = √² = EG² + Gj² 22² + 40 2084 7 E 22 cm EFGHIJ is a solid metal prism of length 40 cm. The cross section EFG is a right-angled triangle. EF=7cm and EG = 22 cm. Calculate the length FJ. FINDING FJ FJ² = FE² + √² =√² = 7² + (25521) 2 FJ² = 2133 3√237 40 BJ² EJ e 22 a E 2√327 FJ = FJ = 46.2 Answer(b) FJ= 46.2 cm [4]
7cm 40cm ر NOT TO SCALE FINDING EJ = √² = EG² + Gj² 22² + 40 2084 7 E 22 cm EFGHIJ is a solid metal prism of length 40 cm. The cross section EFG is a right-angled triangle. EF=7cm and EG = 22 cm. Calculate the length FJ. FINDING FJ FJ² = FE² + √² =√² = 7² + (25521) 2 FJ² = 2133 3√237 40 BJ² EJ e 22 a E 2√327 FJ = FJ = 46.2 Answer(b) FJ= 46.2 cm [4]
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter7: Applying Fractions
Section7.1: Ratios
Problem 28WE
Related questions
Question
Is the solution correct?Why?
![7cm
40cm
ر
NOT TO
SCALE
FINDING
EJ
= √² = EG² + Gj²
22² + 40
2084
7
E
22 cm
EFGHIJ is a solid metal prism of length 40 cm.
The cross section EFG is a right-angled triangle.
EF=7cm and EG = 22 cm.
Calculate the length FJ.
FINDING
FJ
FJ² = FE² + √²
=√² = 7² + (25521) 2
FJ² = 2133
3√237
40 BJ²
EJ
e 22 a
E
2√327
FJ =
FJ =
46.2
Answer(b) FJ=
46.2
cm [4]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe68930b7-6552-46b3-ab6f-1ff15a13eb9f%2F96941879-de94-4098-8862-fc75d66279f3%2F8oxi3tn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7cm
40cm
ر
NOT TO
SCALE
FINDING
EJ
= √² = EG² + Gj²
22² + 40
2084
7
E
22 cm
EFGHIJ is a solid metal prism of length 40 cm.
The cross section EFG is a right-angled triangle.
EF=7cm and EG = 22 cm.
Calculate the length FJ.
FINDING
FJ
FJ² = FE² + √²
=√² = 7² + (25521) 2
FJ² = 2133
3√237
40 BJ²
EJ
e 22 a
E
2√327
FJ =
FJ =
46.2
Answer(b) FJ=
46.2
cm [4]
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