7b.1 Using the determinant, 1 1 (a - k) -(a + k) e+l(a-k).a e-l(a+k).a - i(ak)e+i(a-k).a -i(a+k)e-i(a+k) ai(ß-k)e-i(ß-k).b (B + k) De+i(B+k).b show that the result is given by, -(a²-B²) Ζαβ -1 -(ß-k) - e-l(ß-k).b -1 (B + k) e+i(B+k).b -sin(aa) sin(ßb) + cos(aa) cos(Bb) = cos[k(a + b)]
7b.1 Using the determinant, 1 1 (a - k) -(a + k) e+l(a-k).a e-l(a+k).a - i(ak)e+i(a-k).a -i(a+k)e-i(a+k) ai(ß-k)e-i(ß-k).b (B + k) De+i(B+k).b show that the result is given by, -(a²-B²) Ζαβ -1 -(ß-k) - e-l(ß-k).b -1 (B + k) e+i(B+k).b -sin(aa) sin(ßb) + cos(aa) cos(Bb) = cos[k(a + b)]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![7b.1 Using the determinant,
1
(a - k)
e+i(a-k).a
i(ak)e+i(a-k)a −i(a+k)e-i(a+k)·ai(ß-k)e-i(ß-k).b (B+ k) De+i(B+k).b
0 =
show that the result is given by,
- (a²- ß²)
2αβ
1
-(a + k)
e-i(a+k).a
-1
-(ß-k)
- e-i(ß-k).b
-1
(B + k)
- e+i(B+k).b
-sin(aa) sin(ßb) + cos(aa) cos(Bb) = cos[k(a + b)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92b098b1-776e-4b52-a881-73cea01a37f4%2Ff358b85b-f484-4fcf-a091-bd423eb72c2c%2Fnlxyribn_processed.png&w=3840&q=75)
Transcribed Image Text:7b.1 Using the determinant,
1
(a - k)
e+i(a-k).a
i(ak)e+i(a-k)a −i(a+k)e-i(a+k)·ai(ß-k)e-i(ß-k).b (B+ k) De+i(B+k).b
0 =
show that the result is given by,
- (a²- ß²)
2αβ
1
-(a + k)
e-i(a+k).a
-1
-(ß-k)
- e-i(ß-k).b
-1
(B + k)
- e+i(B+k).b
-sin(aa) sin(ßb) + cos(aa) cos(Bb) = cos[k(a + b)]
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