7A + 413 A. rate equation PA Rate = K[A] [B] [4] P B. Calculate [A] 1.7 2. 1.4 3..7 4. .7 [B] 1.3 1.3 1.3 2.6 K Rate factor= +3CP (net Consider [A] : 142 4=(2) PA [C] .4 4 8 Ч (1013) = 4 : PA = 2 Consider [B]: 154 Rate factor = (1003) = 1 1 = (2) PB Consider [C] : 143 Rate factor = (-005) = 2 2 = (2) Pc Rate .00 3 -012 .006 .003 : PB = 0 : P₂ = 1 Rate = K[A] [B] [C]' Rate = K[A]²[<]
7A + 413 A. rate equation PA Rate = K[A] [B] [4] P B. Calculate [A] 1.7 2. 1.4 3..7 4. .7 [B] 1.3 1.3 1.3 2.6 K Rate factor= +3CP (net Consider [A] : 142 4=(2) PA [C] .4 4 8 Ч (1013) = 4 : PA = 2 Consider [B]: 154 Rate factor = (1003) = 1 1 = (2) PB Consider [C] : 143 Rate factor = (-005) = 2 2 = (2) Pc Rate .00 3 -012 .006 .003 : PB = 0 : P₂ = 1 Rate = K[A] [B] [C]' Rate = K[A]²[<]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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can you double check my work?
![7A +
413
A. rate equation
PA
PB
Rate = K[A] [B] [C]P
B. Calculate
[A]
1. .7
2. 1.4
3..7
4. .7
K
[B]
1.3
1.3
1.3
2.6
+3CP (net
[C]
.4
4
Consider [A] : 142
·003.
Rate factor = (012) 4
4=(2) PA
;
Consider [C] : 143
.006
Rate factor =
.00 3
2 = (2) Pc
.8
Ч
Consider [B]: 14
Rate factor = (-00) = 1
1 = (2) PB
PA = 2
Rate
.00 3
.012
.006
.003
: PB = 0
= 2
: P₁ = 1
Rate KLA] [B] [
Rate= K[A] [4]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fed6c89db-9898-4241-8992-4661b6dde6df%2F6eef9300-5393-4d6b-8c04-8a1f700a9e23%2F9nwvs7s_processed.png&w=3840&q=75)
Transcribed Image Text:7A +
413
A. rate equation
PA
PB
Rate = K[A] [B] [C]P
B. Calculate
[A]
1. .7
2. 1.4
3..7
4. .7
K
[B]
1.3
1.3
1.3
2.6
+3CP (net
[C]
.4
4
Consider [A] : 142
·003.
Rate factor = (012) 4
4=(2) PA
;
Consider [C] : 143
.006
Rate factor =
.00 3
2 = (2) Pc
.8
Ч
Consider [B]: 14
Rate factor = (-00) = 1
1 = (2) PB
PA = 2
Rate
.00 3
.012
.006
.003
: PB = 0
= 2
: P₁ = 1
Rate KLA] [B] [
Rate= K[A] [4]
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