76 Traffic Lights 76 Traffic Lights 74 Random Balls O Red C Yellow C Green C Red C Yellow Green Display (a) (b) (c)
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Write a
user select one of three lights: red, yellow, or green. When a radio button is
selected, the light is turned on, and only one light can be on at a time (see
Figure 9.36a–b). No light is on when the program starts.
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- 4-A[-10:-1:-15:-2:3] Your answer 5-A(3,4)=17 Your answer 6-C(:1:4) Your answer 7-A(.4)-[4:4:4)Description: There are 5 philosophers sitting around a table and try to eat from the center of the table. 5 chopsticks also lay on the table. Let us call the 5 philosophers in clockwise P1, P2, ...P5. There also 5 chopsticks clockwise S1, S2, ..., S5 on the table. There are only one chopstick between every two philosophers. Every right hand chopstick will have the same index as the philosopher. For example, on the right hand side of P1, the chopstick is called S1. And every left hand side chopstick number is 1+number of the philosopher. A philosopher spend random time to think, then he feel hungry and try to eat. The middle dish can provide enough food for everyone at the same time. But a philosopher only can start to eat when he picked up two chopsticks from left hand side and right hand side to form a pair of chopsticks. If a philosopher take one chopsticks, he will try to fight with neighbours to get another one, and never back off to put down the one in his hand. Once the…Eclipse Java: create a random object with a seed value
- @return index of the point that is closest to the origin, which is (0, 0) * In case of a tie, return the lowest index */ public int closestToOriginIndex() { return 0; }2048 is a single-player puzzle game created by Gabriele Cirulli1. It is played on a 4×4 grid that contains integers ≥2 that are powers of 2. The player can use a keyboard arrow key (left/up/right/down) to move all the tiles simultaneously. Tiles slide as far as possible in the chosen direction until they are stopped by either another tile or the edge of the grid. If two tiles of the same number collide while moving, they will merge into a tile with the total value of the two tiles that collided. The resulting tile cannot merge with another tile again in the same move. Please observe this merging behavior carefully in all Sample Inputs and Outputs. Input The input is always a valid game state of a 2048 puzzle. The first four lines of input, that each contains four integers, describe the 16 integers in the 4×4 grid of 2048 puzzle. The j-th integer in the i-th line denotes the content of the cell located at the i-th row and the j -th cell. For this problem, all integers in the input will…computer graphics simple utilty curvei need to write c#.net and send the designi need same link design and code and output https://www.codeproject.com/Articles/5267642/A-Simple-Utility-for-Drawing-Function-Curves
- Blue-Eyed Island: A bunch of people are living on an island, when a visitor comes with a strangeorder: all blue-eyed people must leave the island as soon as possible. There will be a flight out at8:00pm every evening. Each person can see everyone else's eye color, but they do not know theirown (nor is anyone allowed to tell them). Additionally, they do not know how many people haveblue eyes, although they do know that at least one person does. How many days will it take theblue-eyed people to leave?Chiralitydef is_left_handed(pips): Even though this has no effect on fairness, pips from one to six are not painted on dice any which way, but so that the pips on the opposite faces always add up to seven. (This convention makes it easier to tell when someone tries to use gaffed dice that leave out some spot values.) In each corner of the cube, one value from each pair of opposites 1-6, 2-5 and 3-4 meets two values from the other two pairs of opposites. The math works out correctly in for the 23 = 8 corners of the cube. This still leaves two possibilities how to paint these pips. Look at the corner shared by the faces 1, 2, and 3, and read these numbers clockwise around that corner starting from 1. If these three numbers read out as 1-2-3, that die is left-handed, and if they read out as 1-3-2, that die is right-handed. Analogous to a pair of shoes made separately for the left and right foot, left- and right-handed dice are in one sense identical, yet no matter how you twist and turn,…public boolean add(int idx, PlayerNode value) { if (value == null || idx < 0) { return false; } if (idx == 0) { addToFront(value); return true; } PlayerNode current = start; for (int i = 0; i < idx - 1 && current != null; i++) { current = current.next; } if (current == null) { return false; } value.next = current.next; current.next = value; return true; } How do I remove this loop and make it recursive?
- USE JAVA LANGUAGEPlease help with q2 and 3 pleasepackage com.example.myapplication;import androidx.appcompat.app.AppCompatActivity;import android.os.Bundle;import android.view.View;import android.widget.Button;import android.widget.ListView;public class PlayerActivity2 extends AppCompatActivity {ListView simpleList;String SerialNo[] = {"1", "2", "3", "4", "5", "6","7","8","9","10"};int flags[] = {R.drawable.image1, R.drawable.image2, R.drawable.image3, R.drawable.image4, R.drawable.image5, R.drawable.image6, R.drawable.image7, R.drawable.image8, R.drawable.image9, R.drawable.image10};String Names[] = {"mmm", "nnn", "aaa.", "bbb", "ccc", "ddd","eee jk"," ijk","Virgil jk","gil jklk"};String Score[] = {"1", "2","3", "5", "4", "3","5","5","5","5"};@Overrideprotected void onCreate(Bundle savedInstanceState) {super.onCreate(savedInstanceState);setContentView(R.layout.activity2);simpleList = (ListView)findViewById(R.id.simpleListView);//ArrayAdapter<String> arrayAdapter = new ArrayAdapter<String>(this,…