**Equilibrium Constant Expression***Problem Statement:*Write the Equilibrium Constant Expression for the equation below:\[ 4 \text{NH}_3 (g) + 5 \text{O}_2 (g) \rightleftharpoons 4 \text{NO} (g) + 6 \text{H}_2\text{O} (g) \]*Explanation:*In chemical equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction. The equilibrium constant expression \(K_c\) for the reaction is derived from the concentrations of the reactants and products at equilibrium. For a general reaction:\[ aA + bB \rightleftharpoons cC + dD \]The equilibrium constant expression is given by:\[ K_c = \frac{[\text{C}]^c [\text{D}]^d}{[\text{A}]^a [\text{B}]^b} \]Applying this to the given equation:\[ 4 \text{NH}_3 (g) + 5 \text{O}_2 (g) \rightleftharpoons 4 \text{NO} (g) + 6 \text{H}_2\text{O} (g) \]The equilibrium constant expression can be written as:\[ K_c = \frac{[\text{NO}]^4 [\text{H}_2\text{O}]^6}{[\text{NH}_3]^4 [\text{O}_2]^5} \]

Given equilibrium equation; 4NH3(g) + 5O2(g) <----> 4NO(g) + 6H2O(g) .. (1) A general…

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75. Write the Equilibrium Constant Expression for the equation below: 4 NH3 (g) + 5 02 (g) 4 NO (g) + 6 H2O (g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Equilibrium Constant Expression**

*Problem Statement:*
Write the Equilibrium Constant Expression for the equation below:

\[ 4 \text{NH}_3 (g) + 5 \text{O}_2 (g) \rightleftharpoons 4 \text{NO} (g) + 6 \text{H}_2\text{O} (g) \]

*Explanation:*
In chemical equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction. The equilibrium constant expression \(K_c\) for the reaction is derived from the concentrations of the reactants and products at equilibrium. For a general reaction:

\[ aA + bB \rightleftharpoons cC + dD \]

The equilibrium constant expression is given by:

\[ K_c = \frac{[\text{C}]^c [\text{D}]^d}{[\text{A}]^a [\text{B}]^b} \]

Applying this to the given equation:

\[ 4 \text{NH}_3 (g) + 5 \text{O}_2 (g) \rightleftharpoons 4 \text{NO} (g) + 6 \text{H}_2\text{O} (g) \]

The equilibrium constant expression can be written as:

\[ K_c = \frac{[\text{NO}]^4 [\text{H}_2\text{O}]^6}{[\text{NH}_3]^4 [\text{O}_2]^5} \]

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