72. Two capacitors, a 20 uF and a 30 µF, are connected in parallel to a 60-Hz source. What is the total capacitive reactance? a. 7.96 Q b. 23.16 N c. 42.04 2 d. 53.05 2

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**Question:**

Two capacitors, a 20 µF and a 30 µF, are connected in parallel to a 60 Hz source. What is the total capacitive reactance?

**Options:**

a. 7.96 Ω  
b. 23.16 Ω  
c. 42.04 Ω  
d. 53.05 Ω  

**Explanation:**

When capacitors are connected in parallel, their total capacitance (C_total) is the sum of their individual capacitances. Therefore, the total capacitance is:

\[ C_{\text{total}} = C_1 + C_2 = 20 \, \mu\text{F} + 30 \, \mu\text{F} = 50 \, \mu\text{F} \]

Next, the capacitive reactance (X_c) is calculated using the formula:

\[ X_c = \frac{1}{2 \pi f C_{\text{total}}} \]

Where:
- \( f \) is the frequency (60 Hz),
- \( C_{\text{total}} \) is the total capacitance in farads.

Substitute the values into the formula to find the capacitive reactance:

\[ X_c = \frac{1}{2 \pi \times 60 \times 50 \times 10^{-6}} \]

After calculating, compare the result to the provided options to determine the correct answer.
Transcribed Image Text:**Question:** Two capacitors, a 20 µF and a 30 µF, are connected in parallel to a 60 Hz source. What is the total capacitive reactance? **Options:** a. 7.96 Ω b. 23.16 Ω c. 42.04 Ω d. 53.05 Ω **Explanation:** When capacitors are connected in parallel, their total capacitance (C_total) is the sum of their individual capacitances. Therefore, the total capacitance is: \[ C_{\text{total}} = C_1 + C_2 = 20 \, \mu\text{F} + 30 \, \mu\text{F} = 50 \, \mu\text{F} \] Next, the capacitive reactance (X_c) is calculated using the formula: \[ X_c = \frac{1}{2 \pi f C_{\text{total}}} \] Where: - \( f \) is the frequency (60 Hz), - \( C_{\text{total}} \) is the total capacitance in farads. Substitute the values into the formula to find the capacitive reactance: \[ X_c = \frac{1}{2 \pi \times 60 \times 50 \times 10^{-6}} \] After calculating, compare the result to the provided options to determine the correct answer.
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