72. Two capacitors, a 20 uF and a 30 µF, are connected in parallel to a 60-Hz source. What is the total capacitive reactance? a. 7.96 Q b. 23.16 N c. 42.04 2 d. 53.05 2
72. Two capacitors, a 20 uF and a 30 µF, are connected in parallel to a 60-Hz source. What is the total capacitive reactance? a. 7.96 Q b. 23.16 N c. 42.04 2 d. 53.05 2
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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![**Question:**
Two capacitors, a 20 µF and a 30 µF, are connected in parallel to a 60 Hz source. What is the total capacitive reactance?
**Options:**
a. 7.96 Ω
b. 23.16 Ω
c. 42.04 Ω
d. 53.05 Ω
**Explanation:**
When capacitors are connected in parallel, their total capacitance (C_total) is the sum of their individual capacitances. Therefore, the total capacitance is:
\[ C_{\text{total}} = C_1 + C_2 = 20 \, \mu\text{F} + 30 \, \mu\text{F} = 50 \, \mu\text{F} \]
Next, the capacitive reactance (X_c) is calculated using the formula:
\[ X_c = \frac{1}{2 \pi f C_{\text{total}}} \]
Where:
- \( f \) is the frequency (60 Hz),
- \( C_{\text{total}} \) is the total capacitance in farads.
Substitute the values into the formula to find the capacitive reactance:
\[ X_c = \frac{1}{2 \pi \times 60 \times 50 \times 10^{-6}} \]
After calculating, compare the result to the provided options to determine the correct answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c64c691-4381-4c3b-ba72-71ddf7a7103d%2F52ed81d2-0283-4b0f-9c9c-ea0c17cdd40f%2Ftb396qt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
Two capacitors, a 20 µF and a 30 µF, are connected in parallel to a 60 Hz source. What is the total capacitive reactance?
**Options:**
a. 7.96 Ω
b. 23.16 Ω
c. 42.04 Ω
d. 53.05 Ω
**Explanation:**
When capacitors are connected in parallel, their total capacitance (C_total) is the sum of their individual capacitances. Therefore, the total capacitance is:
\[ C_{\text{total}} = C_1 + C_2 = 20 \, \mu\text{F} + 30 \, \mu\text{F} = 50 \, \mu\text{F} \]
Next, the capacitive reactance (X_c) is calculated using the formula:
\[ X_c = \frac{1}{2 \pi f C_{\text{total}}} \]
Where:
- \( f \) is the frequency (60 Hz),
- \( C_{\text{total}} \) is the total capacitance in farads.
Substitute the values into the formula to find the capacitive reactance:
\[ X_c = \frac{1}{2 \pi \times 60 \times 50 \times 10^{-6}} \]
After calculating, compare the result to the provided options to determine the correct answer.
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