7.On average, what value is expected for the t statistic when the null hypothesis is true? а. О с. 1.96 b. 1 d. t> 1.96
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- Q1// Choose the correct answer with all explanations 1. The standard deviation of binomial distribution is a. Vnpq b. npq c. np?q с. d. np 2. For two correlated variables x and y, if coefficient of correlation between x and y is 0.8014, variance of x and y are 16 and 25 respectively. Then the covariance between x and y is: a. 162.08 b. 16.028 c. 160.28 d. 16.208 3. In how many ways can we sort the letters of the word MANAGEMENT so that the comparative position of vowels and consonants remains the same as in MANAGEMENT? а. 1280 b. 720 с. 960 d. 1080 4. The normal distribution depends on which of the following? a. Mean and standard deviation b. Sample size and probability of success c. Standard deviation and number of success d. Mean and probability of success 5. The successful life of product, the time, the weight and the height are classified as: a. Continuous random variables b. Discrete random variables c. Continuous waiting time variables d. Continuous hyper geometric variables.Q26.3.19 Assume that adults have IQ scores that are normally distributed with a mean of 108 and a standard deviation of 15. Find the third quartile Upper Q 3 , which is the IQ score separating the top 25% from the others.. The third quartile, Upper Q 3 , is nothing . (Round to one decimal place as needed.)
- The length, X (in centimeters) of leaves collected for a biology experiment follow a normal distribution with mean, u and standard deviation, o. For any randomly chosen leaf, we have Р(X > 26.73) — 0.2296 P(X < 49.05) = 0.9946 %3D Find the values of u and o. А. — 17.60, o = 12.33 В. д— 17.60, o = 14.56 С. д 3 22.30, о %3 12.33 D. µ = 22.30, o = 14.56Solve the heat equation u = a?uxx, -o 0, (1) Sk if |x| 118
- (3) The weights of adult black squirrels are known to be normally distributed with mean µ and standard deviation o = 0.12 lbs. A random sample of nine black squirrels gave their average weight to be o.78 lbs. It is hypothesized that due to various reasons the black squirrels are becoming heavier. If the null hypothesis is Ho : H s 0.75 lbs, versus H1 : µ > 0.75 find the p-value The following``answers" have been proposed. (a) By consulting a standard normal table, the p-value is sup P(X9 2 0.78) = P(Z > 1.645) = 0.05. HS0.75 (b) By consulting a standard normal table, the p-value is sup P(X9 2 0.78) = P(Z > 1.00) = 0.1587. HS0.75 (c) By consulting a standard normal table, the p-value is sup P(X9 2 0.78) = P(Z > 0.75) = 0.2266. µ 0.50) = 0.3085. µ<0.75 (e) None of the above The correct answer is (a) (b) (d) N/A (Select One)10.1 am choosing for my experiment a post hoc test that will strictly limit my experiment-wise error rate at 1%. Which test could possible employ? A. Fisher's LSD B. ANOVA C. Tukey's method D. a and CA nutritionist claims that the mean tuna consumption by a person is 3.3 pounds per year. A sample of 60 people shows that the mean tuna consumption by a person is 3.1 pounds per year. Assume the population standard deviation is 1.07 pounds. At a = 0.1, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. Ο Α H0: μ 3.1 Ha: u> 3.1 В. Но: и#3.1 Ha: H= 3.1 c. H0 μ>3.1 Ha: us3.1 D. Ho:µ=3.3 Ha: u#3.3 E. Ho: µs3.3 Ha: µ> 3.3 F. Но: > 3.3 Ha: us3.3 (b) Identify the standardized test statistic, z. (Round to two decimal places as needed.) (c) Find the P-value. Hint: Keep in mind that P-value depends on the type of test. Left-tailed test: P-value=Area (where Area = the number from the table) Right-tailed test: P-value=1-Area Two-tailed test: P-value=2*Area P-value = (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. Compare P with a and then State your conclusion. O A. Fail to reject Ho. There is not…
- Q18. If x ~ N(100, 25) and a random sample ofx of size 16 is obtained. What is the standard deviation of the distribution of the sample mean, x? A. 1.25 B V1.25 C. 25 D. V25 = 55. A major car manufacturer wants to test a new engine to make sure it produces less pollution than average. He takes a sample of 9 of his new engines, and finds on average the pollution output is 16.4 ppm with a sample standard deviation of 2.95ppm. He also knows the average pollution output of current engines is 20 ppm. If we assume this is normally distributed test the claim using a = .01 (а) Но : и 1: 'H (b) Find the critical value(s) (c) Find the test value (d) Accept or reject Ho1)Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -0.305°C and 1.619°C.P(−0.305<Z<1.619)= 2)Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -0.561°C and -0.461°C.P(−0.561<Z<−0.461)=P(-0.561<Z<-0.461)=