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The water pressure acting on a masonry dam varies as shown. If the dam is 20 ft wide, determine the following and show full solutions and fbd
g) Perpendicular distance of resultant force from point O
h) Specific coordinates (x,y) of perpendicular distance of resultant force from point O
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- What would be the resultant force Fof the triangular distributed load and its location d measured from point A. 90 lb/ft 3 ft 5 ft 2 ft > Select one: O a. F= 225 Ib and d= 3.67 ft O b. F= 300 Ib and d=2.5 ft O C.F= 450 ib and d=3.67 ft O d. F= 300 Ib and d= 1.67 ftThe resultant loading force is 2.5 kN/m 3 m KN. 0.5 kN/m B -1 m 1.5 kNConvert 22C to Fahrenheit.
- Q/ Compute the magnitude F of the force which the earth exerts on the moon, Perform the calculation in Newtons. Hint: Please use : F = G mim2 G= 6.673*10" m'/kg.s m-5.976*104 kg mzm-6.673*10" kg r-384398*10The water pressure acting on a masonry dam varies asshown. If the dam is 20 ft wide, determine the following and show full solutions and fbd d) Direction of resultant force from horizontale) Distance of resultant force along x-axis from point Of) Distance of resultant force along y-axis from point OB 0.5 m WAB AB A 1 m Өв
- Based on the diagram, determine the magnitude of resultant vector in the cartesian form.+ y -250 N 2-2) R. 350 N 70° - X 60° 80° 145 N 180 N DIAGRAM OF FORCES AND THEIR ANGLES WITH THE HORIZONTAL Force F,=F.Cos( e ) F,=F.Sin( 0 ) +y 180Sen 80 180 Cos 80 80 %3D 180 145 Sin 60 145 Cos60 60 350 Cos 70 145 350 Sin 70 35070 ニ - X -250 COS 9 0 |-250 Sing0 +x -250 90 ニ R = R, = х - y RESULTANT DIAGRAMThe figure below illustrates a hydraulic jack.a) Calculate the force F1 exerted by the operator to lift a load F2 of 104N, knowing that the diameter of the pump piston is 6 mm while the diameter of the load cylinder is equal to 25 mm. Answer: 576 N b) Determine the diameter of the load cylinder so that the force F1 is equal to 100 N. Answer: 0.06m