7.5) A car, initially at rest, begins moving at time t = 0 with a constant acceleration down a straight track. If the car achieves a speed of 60 miles per hour (88 feet per second) at time t = 8 seconds, what is the car's acceleration? Include units in your answer. acceleration = help (units) How far down the track will the car have traveled when its speed reaches 60 miles per hour? Include units in your answer. distance traveled = help (units)

Q: 5.1 #7

A: Given that                  A=60-1054-403-3502-425, λ=5

Q: 1o.e 4.60

A: trigonometry rule

Q: 10.0

A:

Q: Alt 8. 5. 14.

A:

Q: 1.6+0.4(x+6)+3.2

A: To simplify the expression means writing it in the simplest form.

Q: 6.1 10

A:

Q: 6. 5

A:

Q: 29 14

A: It's trigonometric question so I'm providing hand written solution for better understanding.

Q: 2.3 1/p; (1-P)/p².

A: X~geom(p)

Q: 60.91-2.856

A: We want to find the value  60.91-2.856=?

Q: 8. 2 k=1 3k

A:

Q: 5. 20 52

A:

Q: Number 6.12

A: From part (6.11), Let x be the random variable denote that the amount of snow fall between 1 inch…