7.48 5.02. 4.73. 6.21 3.34 7.15 •6.47

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Question
100%
MATERIALS AND METHOD
1. In the exercise you will need pencil, ruler and graphing paper/or any neat paper and point
rainfall map.
2. A map is given, analyse the map then follow the following procedure to calculate the
aeral precipitation:
a) Draw the area concerned to a suitable scale (1cm = 100m), showing its boundary,
locations of the raingauges in the area and outside but close to the boundary.
b) Join location of the raingauges to form a network of triangles.
c) Draw perpendicular bisectors to the triangle sides. These bisectors form polygons
around the stations.
d) Draw perpendicular bisectors to the triangle sides. These bisectors form polygons
around the stations.
e) Draw perpendicular bisectors to the triangle sides. These bisectors form polygons
around the stations.
f) Compute the average rainfall using the following formula:
PĄA1 + P2A2 + ..+ P„An
Pave
AT
Transcribed Image Text:MATERIALS AND METHOD 1. In the exercise you will need pencil, ruler and graphing paper/or any neat paper and point rainfall map. 2. A map is given, analyse the map then follow the following procedure to calculate the aeral precipitation: a) Draw the area concerned to a suitable scale (1cm = 100m), showing its boundary, locations of the raingauges in the area and outside but close to the boundary. b) Join location of the raingauges to form a network of triangles. c) Draw perpendicular bisectors to the triangle sides. These bisectors form polygons around the stations. d) Draw perpendicular bisectors to the triangle sides. These bisectors form polygons around the stations. e) Draw perpendicular bisectors to the triangle sides. These bisectors form polygons around the stations. f) Compute the average rainfall using the following formula: PĄA1 + P2A2 + ..+ P„An Pave AT
7.48
5.02.
4.73.
6.21
3.34
7.15
•6.47
Transcribed Image Text:7.48 5.02. 4.73. 6.21 3.34 7.15 •6.47
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