I really need help with section e line 5 only. The only blank. study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulatedemergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assignedto each display panel-emergency condition combination. The time (in seconds) required to stabilize the emergency condition wasrecorded. The following table gives the resulting data and the JMP output of a two-way ANOVA of the data.Emergency Condition2Display Panel141725311414243413B1522289121931102129321524283719Least Squares Means EntimatesPanel Estimate Condition Estimate21.50000018.250000117.166667B224.50000025.62500032.16666713.333333Analysis of VarianceSun ofMeanF Ratio32.6713Рrob > F<.0001+SourceDFSquareSquares1482.4583Model11134.7691249.50001531.9583Error4.125C. Total23Effect TestsSun ofNparm DF22F Ratio26.4949100.8047SourceProb > FSquares218.5833<.0001+<.00010.6809Panel3 3 1247. 458316.4167ConditionPanel Condition660.6633Tukey HSD All Pairwise ComparisonsQuantile = 2.66776, Adjusted DF = 12.0, Adjustment = Tukey-Panel Difference Std Error t Ratio Prob>|t| Lower 95% Upper 9585.95912-1.41588Panel0.0194+0.0042+B3.25000 1.0155053.200.5409-4.125001.015505-4.06-6.8341-7.375001.015505-7.26< .0001*-10.0841-4.66588Tukey HSD All Pairwise ComparisonsQuantile = 2.9688, Adjusted DF = 12.0, Adjustment = TukeyCondition -Condition Difference Std Error t RatioProb>|t|Lower 95 Upper 95%12-7.3333 1.172604-6.250.0002. -10.8146-3.85211-15.00001.172604-12.79<.0001.-18.4812-11.5188143.83331.1726043.270.0297.0.0001.-11.14790.35217.31463-7.66671.172604-6.54-4.1854411.16671.1726049.52<.00017.685414.647918.8333 1.17260416.06< .000115.352122.3146E Click here for the Excel Data File(a) Interpret the interaction plot in Figure 12.12. Then test for interaction with a= 05.Panel B requiresless timeto stabilize the emergency condition.F(int)= .6633, p-value= .6809;cannotreject HO, no interaction exists.(b) Test the significance of display panel effects with a = .05.F = 26.4949, p-value = .0001;rejectHOно(c) Test the significance of emergency condition effects with a= .05.F =100.8047, p-value-.0001; rejectHO (d) Make pairwise comparisons of display panels A, B, and Cby using Tukey simultaneous 95 percent confidence intervals.(Roundyour answers to 4 decimal places. Negative amounts should be indicated by a minus sign.)0.54095.9591](1.4159) ](4.6659) )HA - µB:(6.8341)(10.0841).LA - pC:pB - uC:(e) Make pairwise comparisons of emergency conditions 1, 2, 3, and 4 by using Tukey simultaneous 95 percent confidence intervals.(Round your answers to 4 decimal places. Negative amounts should be indicated by a minus sign.)u1- u2:p1- u3:(3.8521))(11.5188) ]7.3146 ](4.1854)]14.6479](10.8146)(18.4812)p1- p4:0.3521u2 - u3:(11.1479)u2 - u4:p3 - u4:22.3146 ]15.3521(f) Which display panel minimizes the time required to stabilize an emergency condition? Does your answer depend on theemergency condition? Why?Panel BNominimizes the time required to stabilize an emergency condition.there isnointeraction.(g) Calculate a 95 percent (individual) confidence interval for the mean time required to stabilize emergency condition 4 using displaypanel B. (Round your answers to 2 decimal places.)6.37.12.63 ]Confidence interval

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7.3146 A study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panel-emergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the JMP output of a two-way ANOVA of the data. Emergency Condition 2 Display Panel 4 17 14 15 12 21 31 34 20 25 14 24 13 22 31 32 28 37 19 19 10 29 15 24 Least Squares Means Estimates Panel Estimate Condition Entimate 1 17.166667 24.500000 32.166667 13.333333 21.500000 18.250000 25.625000 1 2 4 Analysin of Variance Sum of Mean Source F Ratio Dr 11 12 23 Squares 1482.4583 Square 134.769 Model 32.6713 Error c. Total 49.5000 1531.9583 4.125 Prob > <.0001 F Effect Tests Sun of F Ratio 26.4949 Source Nparm Dr Prob >P Squares 2 2 216. 5833 3 3 1247.4583 6 6 Panel <.0001 Condition Panel* Condition 100.8047 <.0001 16.4167 0.6633 0.6809 Tukey HSD All Pairwise Comparisons Quantile 2.66776, Adjusted DF = 12.0, Adjustment = Tukey Prob> t| Lower 95 Upper 95% Panel -Panel Difference Std Error t Ratio 3.25000 1.015505 -4.12500 1.015505 3.20 -4.06 0.0194 0.5409 5.95912 0.0042 < .0001+ -10.0841 -4.66588 -6.8341 -1.41588 -7.37500 1.015505 -7.26 Tukey HSD All Pairwise Comparisons Quantile 2.9688, Adjusted DF = 12.0, Adjustment = Tukey Condition -Condition Difference Std Error t Ratio Prob>|t| Lower 95 Upper 95 0.0002. -10.0146 <.0001. -18.4812 -11.5188 -3.8521 -7.3333 1.172604 -15.0000 1.172604 3.8333 1.172604 -6.25 -12.79 3.27 4 0.0297 0.3521 -7.6667 1.172604 0.0001. -11.1479 -6.54 9.52 16.06 -4.1854 11.1667 1.172604 18.8333 1.172604 <.0001 7.6054 14.6479 <.0001 15.3521 22.3146 Click here for the Excel Data File (a) Interpret the interaction plot in Figure 12.12. Then test for interaction with a=.05. Panel B requires Ness time F(int)» .6633, p-value= .0809: to stabilize the emergency condition. cannot reject H0, no interaction exists. (b) Test the significance of display panel effects with a= .05. F = 26.4949, p-value = .0001; roject HO (c) Test the significance of emergency condition effects with a =.05. F 100.8047, p-value -.,0001; reject но