7.3.6= Question HelpTo construct a confidence interval using the given confidence level, do whichever of the following is appropriate. (a) Find the critical value za/2, (b) findthe critical value ta/2, or (c) state that neither the normal nor the t distribution applies.99%; n= 300; o is unknown; population appears to be skewedi t-tableClick here to view a table of critical t-values.Click here to view page 1 of the standard normal table.Click here to view page 2 of the standard normal table.Choose the correct answer below.t distribution: Critical t valuesArea in One Tail0.0250.0050.010.050.10O A. Z/2 = 1.645Degrees ofArea in Two TailsFreedom0.010.020.050.100.20O B. tw/2 = 2.592163.65731.82112.7066.3143.078O c. ta/2 = 1.9689.9256.9654.3032.9201.886%3D5.8414.6044.5413.1822.7762.3531.6383.7472.1321.533O D. za/2 = 2.5754.0323.7073.3652.5712.0151.4763.1432.4471.9431.8956.1.4403.4992.9982.3651.4153.3553.2502.3062.2622.8961.8601.397Click to select your answer and then click Check Answer.2.8212.7641.8331.383103.1691.8121.3722.2282201All parts showing113. Ю62.7181.7961.363

Assumptions for using t statistic: The t statistic is used when the sample size is small (<30).…

Answered: 7.3.6 = Question Help To construct a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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(0 complete) HW Score: 0%, 0 6.2.3 Question Help Find the critical value t, for the confidence level c 0.90 and sample size n= 27. Click the icon to view the t-distribution table. t-Distribution Table t=(Round to the nearest thousandth as needed.) 1.533 2.132 2.776 3.747 4.604 4. 1.476 2.015 2.571 3.365 4.032 5n 6. 1.440 1.943 2.447 3.143 3.707 6. 1.415 1.895 2.365 2.998 3.499 7 8. 1.397 1.860 2.306 2.896 3.355 8. 9. 1.383 1.833 2.262 2.821 3.250 9. 10 1.372 1.812 2.228 2.764 3.169 10 11 1.363 1.796 2.201 2.718 3.106 11 12 1.356 1.782 1.771 2.179 2.681 3.055 12 13 1350 2.160 2.650 3.012 13 14 1.345 1.761 2.145 2.624 2.977 14 15 1.341 1.753 2.131 2.602 2.947 15 16 1.337 1.746 2.120 2.583 2.921 16 17 1.333 1.740 2.110 2.567 2.898 17 18 1.330 1.734 2.101 2.552 2.878 18 19 1.328 1.729 2.093 2.539 2.861 19 20 1.325 1.725 2.086 2.528 2.845 20 21 1.323 1.721 2.080 2.518 2.831 21 22 1.321 1.717 2.074 2.508 2.819 22 23 1.319 1.714 2.069 2.500 2.807 23 24 1.318 1.711 2.064 2.492 2.797 24 25…
X Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. f a. What is the number of degrees of freedom that should be used for finding the critical value /? df = 0 (Type a whole number.) b. Find the critical value a/2 corresponding to a 95% confidence level. a/2= (Round to two decimal places as needed.) c. Give a brief general description of the number of degrees of freedom. D 5373255.docx OA. The number of degrees of freedom for a collection of sample data is the number of sample values that are determined after certain restrictions have been imposed on all data values. OB. The number of degrees of freedom for a collection of sample data is the number of sample values that can vary after certain restrictions have been imposed on all data values. OC. The number of degrees of freedom for a collection of sample data is the total number of sample values. OD. The number of degrees of freedom for a collection…
Use the given confidence interval to find the margin of error and the sample mean. (15.3,23.7) The sample mean is . (Type an integer or a decimal.) The margin of error is. (Type an integer or a decimal.)
Traumatic Brain Injuries have been shown to affect brain volume. A psychologist measures the brain volume of N=8 TBI patients at 2 months and 12 months after their injuries. Evaluate the results of her data using α = .052tail. **Attached Image** a. Show how the 95% confidence interval was calculated. b. State the conclusion in APA format.
Find the critical value t, for the confidence level c = 0.99 and sample size n = 12. Click the icon to view the t-distribution table. (Round to the nearest thousandth as needed.) View an example Get more help - Help me solve this
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The mayor is interested in finding a 90% confidence interval for the mean number of pounds of trash per person per week that is generated in the city. The study included 212 residents whose mean number of pounds of trash generated per person per week was 37.9 pounds and the standard deviation was 7.7 pounds. Round answers to 3 decimal places where possible. b. With 90% confidence the population mean number of pounds per person per week is between _______ and ________ pounds. c. If many groups of 212 randomly selected members are studied, then a different confidence interval would be produced from each group. About __________ percent of these confidence intervals will contain the true population mean number of pounds of trash generated per person per week and about ____________ percent will not contain the true population mean number of pounds of trash generated per person per week.
Use the given confidence interval to find the margin of error and the sample mean. (13.4,21.6) The sample mean is (Type an integer or a decimal.)
n1=16 x‾1=124 s1=35 n2=12 x‾2=86 s2=31 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 : Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places. Step 3 of 3 : Please also find the high and low endpoints and round to four decimal points.
Scores on an English test from 30 students in Class One has a mean of 33 and a standard deviation of 7.2. Scores on an English test from 40 students in Class Two has a mean of 39 and a standard deviation of 5.5. Assuming the two classes are independent, construct a 90%confidence interval for difference between the mean scores for Class One and Class Two. Round your answer to 3 decimal places. Base on the confidence interval, what conclusion can you draw? Group of answer choices (-8.530,-3.470) Group 2 is bigger (-8.530,-3.470) Group 1 is bigger (-8.639,-3.361) No conclusion (-8.639,-3.361) Group 2 is bigger (-6.769,-5.231) Group 2 is bigger
Use the given confidence interval to find the margin of error and the sample mean. (13.2,20.6) The sample mean is The margin of error is (Type an integer or a decimal ) (Type an integer or a decimal)

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