7.29 A gearbox operating at steady state receives 4 hp along the input shaft and delivers 3 hp along the output shaft. The outer surface of thegearbox is at 130°F. For the gearbox,(a) determine, in Btu/s, the rate of heat transfer and(b) perform a full exergy accounting, in Btu/s, of the input power. Let To 70°F.

(a)Write the expression for exergy balance.

Answered: 7.29 A gearbox operating at steady…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Example 5.23. When a closed system executes a certain non-flow process, the work and heat interactions per degree rise in temperature at each temperature attained are given by SW = (4 0.08 T) kJ/kg and 8Q = 1.00 kJ/K dT dT Make calculations for the increase or decrease in the internal energy of the system if it is to operate between the temperature limits of 200 °C and 400 °C.
pls answer all the given thanks
A system undergoes a refrigeration cycle while receiving Qc by heat transfer at temperature Tc and discharging energy Qu by heat transfer at a higher temperature TH. There are no other heat transfers. (a) Using energy and exergy balances, show that the net work input to the cycle cannot be zero. (b) Show that the coefficient of performance of the cycle can be expressed as: Tc TH – TeA'¯ T(Qn – Q). B = where E, is the exergy destruction and To is the temperature of the exergy reference environment. (c) Using the result of part (b), obtain an expression for the maximum theoretical value for the coefficient of performance.
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Please provide complete solution with units of measurement.
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10. A thermodynamic cycle using water is shown on the T-s diagram of Figure 7.26. Calculate the coefficient of performance for this cycle using the equation h, – h, COP = (h, – he) – (h, – hɔ) State A State B State C State D X = 1.00 P = 300. psia X = 0.00 Po = 10.0 psia P = 10.0 psia The processes are A → B = isentropic compression, B → C = isobaric expansion, C →D= isentropic expansion, D - A = isothermal compression. FIGURE 7.26
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