7.26. The sampling theorem, as we have derived it, states that a signal x(t) must be sam-pled at a rate greater than its bandwidth (or equivalently, a rate greater than twice itshighest frequency). This implies that if x(t) has a spectrum as indicated in FigureP7.26(a) then x(t) must be sampled at a rate greater than 2w2. However, since thesignal has most of its energy concentrated in a narrow band, it would seem reason-able to expect that a sampling rate lower than twice the highest frequency could beused. A signal whose energy is concentrated in a frequency band is often referred toas a bandpass signal. There are a variety of techniques for sampling such signals,generally referred to as bandpass-sampling techniques.x(t)X(jw)1-02-01(a)+00p(t) 8(t-nT)Xp (t)W1W2WH(jw)x(t)p(t)H(jw)1Tдід.Wa(b)WawFigure P7.26Chap. 7Problems565To examine the possibility of sampling a bandpass signal as a rate less thanthe total bandwidth, consider the system shown in Figure P7.26(b). Assuming thatww2w1, find the maximum value of T and the values of the constants A, wa,and wb such that x,(t) = x(t).

this problem which is about building a state space model for a system of nonlinear equations and…

Answered: 7.26. The sampling theorem, as we have…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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on matlab code is needed with output
0 1 0 1 1 1 1 0 For the K-map above where the x input is down and the y input is across, which one of these is a simplified expression? F(x, y) = xy x+/y→ F(x, y) = y F(x, y) = x +y' F(x, y) = x + y' F(x, y) = x + y Truth Table F(x, y) = (xy)'
4.1 Show how the function f (W1, w2, w3) =Em(0, 2, 3, 4, 5, 7) can be implemented using a 3-to-8 binary decoder and an OR gate. *4.3 Consider the function f = wiW3 +W2W3 +W¡W2. Use the truth table to derive a circuit for f that uses a 2-to-1 multiplexer.
2.3.2. Canonical Two-Level Implementation of a Boolean Function Truth tables are very helpful to build two-level circuits for a Boolean function. There are two forms of two- level implementations: SOP (sum-of-products) and POS (product-of-sums). Altınbaş University EE242 Digital Systems Laboratory Departmant of Electrical and Electronies Engineering Level 2 Level 1 POS (Product of Sums) SOP (Sum of Products)
For a single-layer perceptron, which statement is true for a viable error function? Here w.x denotes the weighted sum of inputs. E=1 for any input for which the output is 1 and the classification is incorrect. E=-w.x for any input for which the output is 1 and the classification is correct. E=-1 for any input for which the output is 1 and the classification is correct. E=w.x for any input for which the output is 1 and the classification is incorrect.
which is trefers to time shifting of discrete time signal: a.x(n) = z(n-k) b.x(n) = z(-n-k) c.x(n) =-z(n-k) d.x(n) = z(n+k)
The minimum POS for F(A,B,C,D)= M(0, 1, 2, 11, 15) ID(3, 4, 5, 7, 13) is: O (A+C)(A' + D') O (A + B)(C+D')(A' + D') O (A' + B')(C+ D) O (A + B)(C' + D') O none of these
1.Consider the following truth table where Z= F(A,B,C). A B 1 1 1 1 1 1 1 1 1 1 1 (a)Show the sum of products representation for Z. (b) Use k-maps to minimize Z directly from the truth table (c)Use a 2-var mux to realize the Z function from the truth table 2.(a) Fill out the truth table for 1-bit full adder below for Sum and Cout A В Cin Sum Cout 1 1 1 1 1 (b)Show a 2-level logic circuit corresponding to sum.(after minimizing) (c)Show a 2-level logic circuit corresponding to Cout.(after minimizing)
2. Consider a unit-energy root-raised-cosine (RRC) pulse which spans over 8 symbol durations. We take 10 samples per symbol (sps) from this RRC pulse. Write an RRC filter function that employs pulse-shaping using the RRC pulse described above. (If there is a single symbol and s=[1 0], the energy of the corresponding length-81 samples vector should be equal to 1.) The parameters of the RRC pulse are roll-off factor, span, and samples per symbol. You should write your pulse-shaping function according to the prototype given below txFilt = myRRCFilter(s, rf, span, sps) where txFilt is the pulse-shaped signal (transmitted signal), s denotes the transmitted symbols, rf is the roll-off factor, span is the span of the filter, and sps is the samples per symbol.
4. A Moore model finite state machine that acts as a "1011" sequence detector is to be designed using behavioral VHDL. Your design should detect overlapping sequences. Assume the input is named A, the output is named Z and that an active low reset signal asynchronously resets the machine. The VHDL ENTITY is given. Write the corresponding VHDL ARCHITECTURE to implement the FSM. Implement positive edge triggered flip-flops. library ieee; use ieee.std_logic_1164.all; entity fsm is port (a: in std_logic; clk: in std logic; reset n: in std_logic; z: out std_logic); end fsm; a) Draw the Moore model state diagram for the FSM. b) Write the VHDL architecture construct to implement the FSM.
Question 10 Let (w w is in (0,1) and w ends with a 0} Q- (q0, q1, q2) T= (0, 1, B} E= {0, 1} F-(q2) go is the start state and the "scan right" state, until hits B qi is the verify 0 state q2 is the final state So the maching transition function will be: A) alq0.0) =(q0,.0,R). (g0.1) =(q0,1,R) . 0(q0.B) =(q1,8,), a(q1.0) (q2,0,R) B) a(q0.0) =(q0,0,R), a(q0,1) =(q1,1,R), d(q0,B)-(q1,6,L). a(q1.0) =(q2,0,R) O Calq0.0) =(q0,0,R). (q0.1) =(q0, 1.).0(q0.8) -(q1,B.R), a(a1.0) =(q2.0.R) O D) ag0.0) (g0.O, R). Olgo, 1) =(q0,1,R), d(q0,B) =(41,8,U. q1.0) =(gt.O.R)
1. Use k-map to simplify the following expression: AC + ABD + ABD + BCD 2. Express the function of the table to its minimum SOP form by using a k-map. Y 1 1 0 ABC 000 0 1 1 0 0 0 ---0 1 1 OOOOD 0 0 0 3. Express the function of the table to its minimum POS form by using a k-map. A 0 OOOO------- 0 1 0 1 1 1 0 1 1 BOOOO В 0 0 0 1 0 1 0 0 blooo 1000 с 1 1 1 0 1 COTTOOTE DO 0 1 1 1 1 0 0 1 0 1 1 1 1 0 0 HO 0 OTO 1 0 1 0 TOTOHOTO 0 0 1 0 1 0 0 1 1 1 0 1 0 1 1 1 1 0 1 1 Y 0 1 1 0 0 0 1 1 1 0 1 0 1 1 0 1

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