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7.22 Report a p-value corresponding to your results in Problem 7.21. Suppose we wish to test the hypothesis H.: μ = 45 vs. H₁: u> 45. 7.23 What will be the result if we conclude that the mean is greater than 45 when the actual mean is 45? (i) We have made a type I error. (ii) We have made a type II error. (iii) We have made the correct decision.

7.22 Report a p-value corresponding to your results in Problem 7.21. Suppose we wish to test the hypothesis H.: μ = 45 vs. H₁: u> 45. 7.23 What will be the result if we conclude that the mean is greater than 45 when the actual mean is 45? (i) We have made a type I error. (ii) We have made a type II error. (iii) We have made the correct decision.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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270 CHAPTER 7 Hypothesis Testing: One-Sample Infere 7.22 Report a p-value corresponding to your results in Problem 7.21. Suppose we wish to test the hypothesis H.: μ = 45 vs. H₁: u > 45. 7.23 What will be the result if we conclude that the mean is greater than 45 when the actual mean is 45? € €€ € (i) We have made a type I error. || (ii) We have made a type Il error. (iii) We have made the correct decision. 7.24 What will be the result if we conclude that the mean is 45 when the actual mean is 50? (i) We have made a type I error. (ii) We have made a type II error. (iii) We have made the correct decision. Suppose we wish to test H: μ = 30 vs. H₁: μ#30 based on a sample of size 31. bu 7.25 Which of the following sample results yields the small- est p-value and why? x (i) X = 28, s = 6 (ii) X = 27, s=4 (iii) X = 32, s=2 x (iv) X = 26, s = 9 not OPA Cancer 7.26 Suppose we identify 50 womon 50 *7 ar ha OW 50 D *7 hy ity 5 di C T 1 1 a fo C b P 7 7 7 C
Transcribed Image Text:270 CHAPTER 7 Hypothesis Testing: One-Sample Infere 7.22 Report a p-value corresponding to your results in Problem 7.21. Suppose we wish to test the hypothesis H.: μ = 45 vs. H₁: u > 45. 7.23 What will be the result if we conclude that the mean is greater than 45 when the actual mean is 45? € €€ € (i) We have made a type I error. || (ii) We have made a type Il error. (iii) We have made the correct decision. 7.24 What will be the result if we conclude that the mean is 45 when the actual mean is 50? (i) We have made a type I error. (ii) We have made a type II error. (iii) We have made the correct decision. Suppose we wish to test H: μ = 30 vs. H₁: μ#30 based on a sample of size 31. bu 7.25 Which of the following sample results yields the small- est p-value and why? x (i) X = 28, s = 6 (ii) X = 27, s=4 (iii) X = 32, s=2 x (iv) X = 26, s = 9 not OPA Cancer 7.26 Suppose we identify 50 womon 50 *7 ar ha OW 50 D *7 hy ity 5 di C T 1 1 a fo C b P 7 7 7 C
is ed 20 re n S Problem 7.19. Genetics Ribosomal 5S RNA can be represented as a sequence of 120 nucleotides. Each nucleotide can be represented by one of four characters: A (adenine), G (guanine), C (cytosine), or U (uracil). The characters occur with different probabilities for each position. We wish to test whether a new sequence is the same as ribosomal 5S RNA. For this purpose, we replicate the new sequence 100 times and find there are 60 A's in the 20th position. 7.21 If the probability of an A in the 20th position in ribosomal 5S RNA is .79, then test the hypothesis that the new sequence is the same as ribosomal 5S RNA using the critical-value method.
Transcribed Image Text:is ed 20 re n S Problem 7.19. Genetics Ribosomal 5S RNA can be represented as a sequence of 120 nucleotides. Each nucleotide can be represented by one of four characters: A (adenine), G (guanine), C (cytosine), or U (uracil). The characters occur with different probabilities for each position. We wish to test whether a new sequence is the same as ribosomal 5S RNA. For this purpose, we replicate the new sequence 100 times and find there are 60 A's in the 20th position. 7.21 If the probability of an A in the 20th position in ribosomal 5S RNA is .79, then test the hypothesis that the new sequence is the same as ribosomal 5S RNA using the critical-value method.
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