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7.2.3 Calculate the mean number of renewals M(n) =E[N(n)] for the renewal process having interoccurrence distribution P₁ = 0.4, p2 = 0.1, p3=0.3, P4 = 0.2 for n = 1, 2,..., 10. Also calculate un = M(n) - M(n - 1). 7.2.3 n M(n) u(n) 1 0.4 0.4 2 0.66 0.26 3 1.104 0.444 4 1.6276 0.5236 5 2.0394 0.41184 6 2.4417 0.4023 7 2.8897 0.44798 8 3.3374 0.44769 9 3.7643 0.42693 10 4.1947 0.4304

7.2.3 Calculate the mean number of renewals M(n) =E[N(n)] for the renewal process having interoccurrence distribution P₁ = 0.4, p2 = 0.1, p3=0.3, P4 = 0.2 for n = 1, 2,..., 10. Also calculate un = M(n) - M(n - 1). 7.2.3 n M(n) u(n) 1 0.4 0.4 2 0.66 0.26 3 1.104 0.444 4 1.6276 0.5236 5 2.0394 0.41184 6 2.4417 0.4023 7 2.8897 0.44798 8 3.3374 0.44769 9 3.7643 0.42693 10 4.1947 0.4304

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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7.2.3 Calculate the mean number of renewals M(n) =E[N(n)] for the renewal process having interoccurrence distribution P₁ = 0.4, p2 = 0.1, p3=0.3, P4 = 0.2 for n = 1, 2,..., 10. Also calculate un = M(n) - M(n - 1).
Transcribed Image Text:7.2.3 Calculate the mean number of renewals M(n) =E[N(n)] for the renewal process having interoccurrence distribution P₁ = 0.4, p2 = 0.1, p3=0.3, P4 = 0.2 for n = 1, 2,..., 10. Also calculate un = M(n) - M(n - 1).
7.2.3 n M(n) u(n) 1 0.4 0.4 2 0.66 0.26 3 1.104 0.444 4 1.6276 0.5236 5 2.0394 0.41184 6 2.4417 0.4023 7 2.8897 0.44798 8 3.3374 0.44769 9 3.7643 0.42693 10 4.1947 0.4304
Transcribed Image Text:7.2.3 n M(n) u(n) 1 0.4 0.4 2 0.66 0.26 3 1.104 0.444 4 1.6276 0.5236 5 2.0394 0.41184 6 2.4417 0.4023 7 2.8897 0.44798 8 3.3374 0.44769 9 3.7643 0.42693 10 4.1947 0.4304
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