7.17) Write the inOrder() method, which has an array of integers as a parameter, and returns true if the numbers are sorted (in order from low to high) or false otherwise. The program outputs "In order" if the array is sorted, or "Not in order" if the array is not sorted. Ex: If the array passed to the inOrder() method is [5, 6, 7, 8, 3], then the method returns false and the program outputs: Not in order Ex: If the array passed to the inOrder() method is [5, 6, 7, 8 , 10], then the method returns true and the program outputs: In order Code: public class Sorting { public boolean inOrder(int [] nums) { /* Type your code here. */ } public static void main(String[] args) { Sorting s = new Sorting(); // Test out-of-order example. int [] nums1 = {5, 6, 7, 8, 3}; if(s.inOrder(nums1)){ System.out.println("In order"); }else{ System.out.println("Not in order"); }
7.17)
Write the inOrder() method, which has an array of integers as a parameter, and returns true if the numbers are sorted (in order from low to high) or false otherwise. The
Ex: If the array passed to the inOrder() method is [5, 6, 7, 8, 3], then the method returns false and the program outputs:
Not in order
Ex: If the array passed to the inOrder() method is [5, 6, 7, 8 , 10], then the method returns true and the program outputs: In order
Code:
public class Sorting {
public boolean inOrder(int [] nums) {
/* Type your code here. */
}
public static void main(String[] args) {
Sorting s = new Sorting();
// Test out-of-order example.
int [] nums1 = {5, 6, 7, 8, 3};
if(s.inOrder(nums1)){
System.out.println("In order");
}else{
System.out.println("Not in order");
}
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 6 images
