7. What is the output of the following code? String st "dog"; for (int ax = 0; aX < st.length(); aX++) { bX++) { = for (int bX } = 1; bx <= aX; System.out.print(" "); } for (int cX = ax; cx <= st.length () / 2 + 1; cX++) { System.out.print (st.charAt(aX)); //returns the char at specified index } System.out.println();
7. What is the output of the following code? String st "dog"; for (int ax = 0; aX < st.length(); aX++) { bX++) { = for (int bX } = 1; bx <= aX; System.out.print(" "); } for (int cX = ax; cx <= st.length () / 2 + 1; cX++) { System.out.print (st.charAt(aX)); //returns the char at specified index } System.out.println();
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
how would you run through this code step by step? i’m a bit confused. this is a non graded practice
Expert Solution
Step 1: Algorithm for the given code:
- Start by defining a string st with the value "dog."
- Initialize a loop variable aX to 0 and set the loop condition to iterate while aX is less than the length of the string st.
- Inside the outer loop, initialize a nested loop variable bX to 0. This loop is responsible for printing spaces before the characters. Set the loop condition to iterate while bX is less than aX.
- Inside the innermost loop, initialize a variable cX to the current value of aX. This loop is responsible for printing the characters.
- In the innermost loop, print the character at the aX position of the string st repeatedly from cX to the end of the string.
- After the innermost loop, move to a new line by using System.out.println() to create the next row of the triangular pattern.
- Repeat the process by incrementing the aX variable in the outer loop and continue until aX is equal to or greater than the length of the string st.
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