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7. Using Kirchoff's current law, the current for node c B gives: 1 + I = I3. Using Kirchoff's voltage law, in the loop EFAB gives: -411+(-30)-51–101,+(-60) – 101, = 0. Using Kirchoff's voltage law, in the loop BCDE gives: -30/ + 120 – 101, + 60 = 0 B R,-102 R-30 2 E-60 V R-102 (a) Write down the equations as a system of three linear equations. -120 V D (b) Use any method to determine the currents 1,12, I, flowing in the circuit. E,-50 V

7. Using Kirchoff's current law, the current for node c B gives: 1 + I = I3. Using Kirchoff's voltage law, in the loop EFAB gives: -411+(-30)-51–101,+(-60) – 101, = 0. Using Kirchoff's voltage law, in the loop BCDE gives: -30/ + 120 – 101, + 60 = 0 B R,-102 R-30 2 E-60 V R-102 (a) Write down the equations as a system of three linear equations. -120 V D (b) Use any method to determine the currents 1,12, I, flowing in the circuit. E,-50 V

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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7. Using Kirchoff's current law, the current for node c B gives: / +I2 = I3. Using Kirchoff's voltage law, in the loop EFAB gives: -411+(-30)-51,–101, +(-60) – 101, = 0. Using Kirchoff's voltage law, in the loop BCDE gives: -30/ + 120 – 101, + 60 = 0 B R,-10 2 R-30 2 ,-60 V R-10Q (a) Write down the equations as a system of three linear equations. -120 V D E,-50V (b) Use any method to determine the currents 1, 12, I, flowing in the circuit.
Transcribed Image Text:7. Using Kirchoff's current law, the current for node c B gives: / +I2 = I3. Using Kirchoff's voltage law, in the loop EFAB gives: -411+(-30)-51,–101, +(-60) – 101, = 0. Using Kirchoff's voltage law, in the loop BCDE gives: -30/ + 120 – 101, + 60 = 0 B R,-10 2 R-30 2 ,-60 V R-10Q (a) Write down the equations as a system of three linear equations. -120 V D E,-50V (b) Use any method to determine the currents 1, 12, I, flowing in the circuit.
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