7. Use the Root Test to determine whether the series is convergent or divergent. Σ Sn Let L=lim "la In=1 A. L= 32, the series is divergent B. L=0, the series is convergent C. L= 48, the series is divergent D. L=1, the series is convergent

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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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7. Use the Root Test to determine whether the series is convergent or divergent.
Σ
5n
Let L=lim "la,l
-2n
n+1
A. L= 32, the series is divergent
B. L= 0, the series is convergent
C. L= 48, the series is divergent
D. L=1, the series is convergent
8. Using the Ratio Test find the radius of convergence and interval of convergence.
an+1
Let L= lim
n-0o I an
2•4•6.....(2n)
A. L= 0, then R=0 and I = 0
B. L= 1, then R =1 and I= (-1, 1)
C.L= 2, then R= 2 and I= (-2, 2)
D. L= 0, then R= 00 and I= (-0,00)
9. Find a Power series representation for the function and determine the radius of
convergence and interval of convergence.
xta
f(x)
=
x²+q3 , a >0
(-1)"x²"
A. f(x) =
,R = a and 1= (-a, a)
a2n+1
"n=0
(-1)"x"
B. f(x) =
,R= a and 1= (-a, a)
an+1
00
(-1)"x²n
C. f(x) =
, R= 2a and | = (-2a,2a)
a2n+1
(-1)"x"
D. f(x) =
R= 2a and 1=(-2a,2a)
an+1
3
Transcribed Image Text:7. Use the Root Test to determine whether the series is convergent or divergent. Σ 5n Let L=lim "la,l -2n n+1 A. L= 32, the series is divergent B. L= 0, the series is convergent C. L= 48, the series is divergent D. L=1, the series is convergent 8. Using the Ratio Test find the radius of convergence and interval of convergence. an+1 Let L= lim n-0o I an 2•4•6.....(2n) A. L= 0, then R=0 and I = 0 B. L= 1, then R =1 and I= (-1, 1) C.L= 2, then R= 2 and I= (-2, 2) D. L= 0, then R= 00 and I= (-0,00) 9. Find a Power series representation for the function and determine the radius of convergence and interval of convergence. xta f(x) = x²+q3 , a >0 (-1)"x²" A. f(x) = ,R = a and 1= (-a, a) a2n+1 "n=0 (-1)"x" B. f(x) = ,R= a and 1= (-a, a) an+1 00 (-1)"x²n C. f(x) = , R= 2a and | = (-2a,2a) a2n+1 (-1)"x" D. f(x) = R= 2a and 1=(-2a,2a) an+1 3
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