7. Titration of valine by a strong base, for example NaOH, reveals two pk's. The titration reaction occurring at pk2 (pK2 = 9.62) is: A) RCOOH + OH- → RCOO- + H20 B) RCOOH + R'NH2 → RCOO- + R'NH2* C) RCOO- + RʼNH2* → RCOOH + R'NH2 D) RNH3+ + OH- llowin RNH2 + H2O could be se hromato on)? Please circle your

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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7. Titration of valine by a strong base, for example NAOH, reveals
en
two pk's. The titration reaction occurring at pk2 (pK2 = 9.62) is:
A) RCOOH + OH-
→ RCO0- + H20
B) RCOOH + R'NH2
cha
C) RCOO- + R'NH2*
→ RCOO- + R'NH2+
→ RCOOH + R'NH2
uld be saparated
D) RNH3+ + OH-
→ RNH2 + H20
Transcribed Image Text:7. Titration of valine by a strong base, for example NAOH, reveals en two pk's. The titration reaction occurring at pk2 (pK2 = 9.62) is: A) RCOOH + OH- → RCO0- + H20 B) RCOOH + R'NH2 cha C) RCOO- + R'NH2* → RCOO- + R'NH2+ → RCOOH + R'NH2 uld be saparated D) RNH3+ + OH- → RNH2 + H20
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