7. The total rotational losses of an induction motor are a combination of A) Friction losses C) Core losses. B) Windage losses. D) Stray losses. 8. The developed mechanical power can be calculated using the equation of - A) PAG - PRCL. B). PAG Wsync C) (1-s) PAG. D) 3 E2Gc. 9. For an induction motor, if the synchronous speed is 1800 r/m, and the rotor speed 180rad/sec, then the slip will be: A) 5.5% C) 6% B) 4.5% D) 4%
7. The total rotational losses of an induction motor are a combination of A) Friction losses C) Core losses. B) Windage losses. D) Stray losses. 8. The developed mechanical power can be calculated using the equation of - A) PAG - PRCL. B). PAG Wsync C) (1-s) PAG. D) 3 E2Gc. 9. For an induction motor, if the synchronous speed is 1800 r/m, and the rotor speed 180rad/sec, then the slip will be: A) 5.5% C) 6% B) 4.5% D) 4%
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Transcribed Image Text:7. The total rotational losses of an induction motor are a combination of -------
A) Friction losses
B) Windage losses.
D) Stray losses.
C) Core losses.
8. The developed mechanical power can be calculated using the equation of-
A) PAG - PRCL.
B)
PAG
w sync
C) (1-s) PAG.
D) 3 E2Gc.
9. For an induction motor, if the synchronous speed is 1800 r/m, and the rotor speed
180rad/sec, then the slip will be:
A) 5.5%
C) 6%
B) 4.5%
D) 4%
10. The power losses in the stator part of the induction motor are
B) Core losses
D) Friction and windage losses
A) Stator copper losses
C) Air-gap losses
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