[7.] The moment of inertia of a solid sphere is I = mr². The moment of inertia of a ring is I = mr². A sphere and a ring with equal masses (m) and equal radii r both roll up an inclined plane. They start with the same linear velovity v for the center of mass. (a) Without doing a calculation, clearly explain which will go higher. (b) Use conservation of energy to determine the maximum vertical height h the sphere and the ring will reach.

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Chapter1: Units, Trigonometry. And Vectors
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### Problem 7

The moment of inertia of a solid sphere is given by \( I = \frac{2}{5}mr^2 \). The moment of inertia of a ring is \( I = mr^2 \). 

Consider a sphere and a ring, both with equal masses (\(m\)) and equal radii (\(r\)), rolling up an inclined plane. They both start with the same linear velocity (\(v\)) for their center of mass.

#### Part (a):
Without performing any calculations, clearly explain which object (the sphere or the ring) will roll higher up the inclined plane.

#### Part (b):
Using the principle of conservation of energy, determine the maximum vertical height (\(h\)) that both the sphere and the ring will reach.
Transcribed Image Text:### Problem 7 The moment of inertia of a solid sphere is given by \( I = \frac{2}{5}mr^2 \). The moment of inertia of a ring is \( I = mr^2 \). Consider a sphere and a ring, both with equal masses (\(m\)) and equal radii (\(r\)), rolling up an inclined plane. They both start with the same linear velocity (\(v\)) for their center of mass. #### Part (a): Without performing any calculations, clearly explain which object (the sphere or the ring) will roll higher up the inclined plane. #### Part (b): Using the principle of conservation of energy, determine the maximum vertical height (\(h\)) that both the sphere and the ring will reach.
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