Please answer all of the questions pictured below by selecting the correct answer choice for each please. Thank you **Problem Statement:**7. The figure shows a uniform magnetic field that is normal to the plane of a conducting loop with resistance R. Which one of the following changes will cause an induced current to flow through the resistor?Options:A) Decreasing the area of the loop B) Decreasing the magnitude of the magnetic field C) Increasing the magnitude of the magnetic field D) Rotating the loop through 90° about an axis in the plane of the paper E) All of the above **Diagram Explanation:**The diagram displays a rectangular loop through which a current \( I \) flows. The loop is situated in a magnetic field, and the field is normal (perpendicular) to the plane of the loop. The variables \( I \), \( v \), and \( l \) are marked on the diagram, indicating the direction of the current and the dimensions of the loop.

Let us consider a uniform magnetic field (B) that is normal to the plane of a conducting loop with resistance (R) as shown in figure respectively. suppose (ϕ) be the magnetic flux of a conducting loop & A be the area of the conducting loop. we know, (ϕ)=B . A cosθ------------(1) Let us (e) be the induced electromotive force of a conducting loop with resistance (R) having induced current (I) respectively. Now when internal resistance (r) is zero for a conducting loop we know, e=I X R------------(2) According to lenz's Law we conclude that, e=-N (dϕ/dt)----------------(3) Here (N) is the number of loops of conductor. Now putting values of (e) & (ϕ) from (2) & (1) in (3) we get, I X R=-N [d(B . A cosθ)/dt] I X R =- N x B x A d(cosθ)/dt------------(4) Clearly we can see that every thing in constant except induced current (I) and angle (θ) which depends on time. so, (4) can be written as I~d(cosθ)/dt----------(5) Hence we conclude that induced current will change when rotating the loop through 90o about an axis in the plane of the paper. Therefore option (D) is the correct answer.