7. The diagram shows information about the first 8 seconds of a car journey. Speed (m/s) 0 6 Time (seconds) له NOT TO SCALE The car travels with constant acceleration reaching a speed of vm/s after 6 seconds. The car then travels at a constant speed of vm/s for a further 2 seconds. The car travels a total distance of 150 metres. Work out the value of v. DISTANCE = AREA UNDER CURVE D' = A + A D= ± 6h + wil 150 150 ½ (6-0) (v) + (8-6)(v) =(6-0)(v) 1.6. v + 24 1/2 30 150 3V+24 150 = 54 130 7/22 v= 30
7. The diagram shows information about the first 8 seconds of a car journey. Speed (m/s) 0 6 Time (seconds) له NOT TO SCALE The car travels with constant acceleration reaching a speed of vm/s after 6 seconds. The car then travels at a constant speed of vm/s for a further 2 seconds. The car travels a total distance of 150 metres. Work out the value of v. DISTANCE = AREA UNDER CURVE D' = A + A D= ± 6h + wil 150 150 ½ (6-0) (v) + (8-6)(v) =(6-0)(v) 1.6. v + 24 1/2 30 150 3V+24 150 = 54 130 7/22 v= 30
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 7ECP: The kinetic energy E of an object varies jointly with the object’s mass m and the square of the...
Question
Is the solution correct?Why or why not?
![7. The diagram shows information about the first 8 seconds of a car journey.
Speed
(m/s)
0
6
Time (seconds)
له
NOT TO
SCALE
The car travels with constant acceleration reaching a speed of vm/s after 6 seconds.
The car then travels at a constant speed of vm/s for a further 2 seconds.
The car travels a total distance of 150 metres.
Work out the value of v.
DISTANCE =
AREA UNDER CURVE
D' =
A + A
D=
± 6h + wil
150
150
½ (6-0) (v) + (8-6)(v)
=(6-0)(v)
1.6. v + 24
1/2 30
150
3V+24
150 =
54
130
7/22
v=
30](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe68930b7-6552-46b3-ab6f-1ff15a13eb9f%2Fd38e1c08-4155-4ad4-a999-89fbe5d60d43%2F40pwpv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7. The diagram shows information about the first 8 seconds of a car journey.
Speed
(m/s)
0
6
Time (seconds)
له
NOT TO
SCALE
The car travels with constant acceleration reaching a speed of vm/s after 6 seconds.
The car then travels at a constant speed of vm/s for a further 2 seconds.
The car travels a total distance of 150 metres.
Work out the value of v.
DISTANCE =
AREA UNDER CURVE
D' =
A + A
D=
± 6h + wil
150
150
½ (6-0) (v) + (8-6)(v)
=(6-0)(v)
1.6. v + 24
1/2 30
150
3V+24
150 =
54
130
7/22
v=
30
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