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7. The diagram shows information about the first 8 seconds of a car journey. Speed (m/s) 0 6 Time (seconds) له NOT TO SCALE The car travels with constant acceleration reaching a speed of vm/s after 6 seconds. The car then travels at a constant speed of vm/s for a further 2 seconds. The car travels a total distance of 150 metres. Work out the value of v. DISTANCE = AREA UNDER CURVE D' = A + A D= ± 6h + wil 150 150 ½ (6-0) (v) + (8-6)(v) =(6-0)(v) 1.6. v + 24 1/2 30 150 3V+24 150 = 54 130 7/22 v= 30

7. The diagram shows information about the first 8 seconds of a car journey. Speed (m/s) 0 6 Time (seconds) له NOT TO SCALE The car travels with constant acceleration reaching a speed of vm/s after 6 seconds. The car then travels at a constant speed of vm/s for a further 2 seconds. The car travels a total distance of 150 metres. Work out the value of v. DISTANCE = AREA UNDER CURVE D' = A + A D= ± 6h + wil 150 150 ½ (6-0) (v) + (8-6)(v) =(6-0)(v) 1.6. v + 24 1/2 30 150 3V+24 150 = 54 130 7/22 v= 30

Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter61: Areas Of Circles, Sectors, And Segments
Section: Chapter Questions
Problem 24A: A piece shown by the shaded portion is to be cut from a square plate 128 millimeters on a side. a....
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7. The diagram shows information about the first 8 seconds of a car journey. Speed (m/s) 0 6 Time (seconds) له NOT TO SCALE The car travels with constant acceleration reaching a speed of vm/s after 6 seconds. The car then travels at a constant speed of vm/s for a further 2 seconds. The car travels a total distance of 150 metres. Work out the value of v. DISTANCE = AREA UNDER CURVE D' = A + A D= ± 6h + wil 150 150 ½ (6-0) (v) + (8-6)(v) =(6-0)(v) 1.6. v + 24 1/2 30 150 3V+24 150 = 54 130 7/22 v= 30
Transcribed Image Text:7. The diagram shows information about the first 8 seconds of a car journey. Speed (m/s) 0 6 Time (seconds) له NOT TO SCALE The car travels with constant acceleration reaching a speed of vm/s after 6 seconds. The car then travels at a constant speed of vm/s for a further 2 seconds. The car travels a total distance of 150 metres. Work out the value of v. DISTANCE = AREA UNDER CURVE D' = A + A D= ± 6h + wil 150 150 ½ (6-0) (v) + (8-6)(v) =(6-0)(v) 1.6. v + 24 1/2 30 150 3V+24 150 = 54 130 7/22 v= 30
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