7. Suppose X is a continuous random variable with 0 sX s 4 with valid probability density function f(x) = cx and mean E[X]. To THREE decimal places the value of c is and E[X] is 8. Suppose X is a continuous random variable with -1 SXS1 and having valid probability density function f(x) = c(5-4/x|) and variance V[X]. Note that f(x) is symmetric around the point x-0. Rounded to THREE decimal places the value of c is and the value of V[X] is
7. Suppose X is a continuous random variable with 0 sX s 4 with valid probability density function f(x) = cx and mean E[X]. To THREE decimal places the value of c is and E[X] is 8. Suppose X is a continuous random variable with -1 SXS1 and having valid probability density function f(x) = c(5-4/x|) and variance V[X]. Note that f(x) is symmetric around the point x-0. Rounded to THREE decimal places the value of c is and the value of V[X] is
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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please send correct answer Q7
![7. Suppose X is a continuous random variable with 0 sX54 with valid probability density function f(x) = cx and mean E[X].
To THREE decimal places the value of c is
and E[X] is
8. Suppose X is a continuous random variable with -1 sXs 1 and having valid probability density function f(x) = c(5-4|x|) and variance V[X].
Note that f(x) is symmetric around the point x-0.
Rounded to THREE decimal places the value of c is
and the value of V[X] is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F694fce0b-4aa0-4f40-88ae-a3e75435a12b%2F4b06e128-8669-46e0-8b03-b16636a152b6%2Fxl2fo7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7. Suppose X is a continuous random variable with 0 sX54 with valid probability density function f(x) = cx and mean E[X].
To THREE decimal places the value of c is
and E[X] is
8. Suppose X is a continuous random variable with -1 sXs 1 and having valid probability density function f(x) = c(5-4|x|) and variance V[X].
Note that f(x) is symmetric around the point x-0.
Rounded to THREE decimal places the value of c is
and the value of V[X] is
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