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7. Solving an equation in the form x = p is similar to solving equations with squared terms. Complete the table to show the differences. x² = p x = p To solve: Take the square root. Number of solutions and their sign(s): Two solutions. One is positive and one is negative. Example: x? = 144 =±J144 x* =125 X = 112

7. Solving an equation in the form x = p is similar to solving equations with squared terms. Complete the table to show the differences. x² = p x = p To solve: Take the square root. Number of solutions and their sign(s): Two solutions. One is positive and one is negative. Example: x? = 144 =±J144 x* =125 X = 112

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Main idea: Solving equations by taking the cube root 7. Solving an equation in the form x' = p is similar to solving equations with squared terms. Complete the table to show the differences. x² = p x = p To solve: Take the square root. Two solutions. One is positive and one is negative. Number of solutions and their sign(s): Example: x? = 144 * = 125 V = +144 X = X = +12
Transcribed Image Text:Main idea: Solving equations by taking the cube root 7. Solving an equation in the form x' = p is similar to solving equations with squared terms. Complete the table to show the differences. x² = p x = p To solve: Take the square root. Two solutions. One is positive and one is negative. Number of solutions and their sign(s): Example: x? = 144 * = 125 V = +144 X = X = +12
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