7. Solve each equation, if possible. a) 5(3x + 4) – 2x = 7x – 3(-2x + 11) %3D b) –(12x – 21) + 16 = 1 + 4(x + 2) c) –5 – (15x – 1) = 2(7x – 16) – x d) –4x – 2(8x + 1) = – (-2x – 10)
7. Solve each equation, if possible. a) 5(3x + 4) – 2x = 7x – 3(-2x + 11) %3D b) –(12x – 21) + 16 = 1 + 4(x + 2) c) –5 – (15x – 1) = 2(7x – 16) – x d) –4x – 2(8x + 1) = – (-2x – 10)
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter8: Polynomials
Section8.6: Factoring Quadratic Trinomials
Problem 35PPS
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A N3CS21_04 - Math 8 CS 202
A Practice Set 20: 3 through 7b
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c) 12 – -(12x – 8) + 11x
04
d) 12x – 8(-3 – 4x) – 5 + 7x
7. Solve each equation, if possible.
a) 5(3x + 4) – 2.x = 7x – 3(-2x + 11)
b) –(12x – 21) + 16 = 1 + 4(x + 2)
с) -5 — (15х — 1) %3D2(7х — 16) — х
d) –4x – 2(8x + 1) = – (-2x – 10)
8. Resolve the missing length of the following right
triangles; assume c is the hypotenuse. Simplify the
radical expression, if possible (no calculators
needed).
a) c = 6,a = 3,b =
b) c = 12,a = 6,b =
c) c = 10,a = 5,b =
d) c = 16,a = 8,b =
e) a = 2,b = 2,c =
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4 8th grade Zoom Codes.pdf-God
A N3CS21_04 - Math 8 CS 202
A Practice Set 20: 3 through 7b
b My Questions | bartleby
+
A classroom.google.com/c/MT|2OTQOMD9ZNTUZ
N3C
c) 12 – -(12x – 8) + 11x
04
d) 12x – 8(-3 – 4x) – 5 + 7x
7. Solve each equation, if possible.
a) 5(3x + 4) – 2.x = 7x – 3(-2x + 11)
b) –(12x – 21) + 16 = 1 + 4(x + 2)
с) -5 — (15х — 1) %3D2(7х — 16) — х
d) –4x – 2(8x + 1) = – (-2x – 10)
8. Resolve the missing length of the following right
triangles; assume c is the hypotenuse. Simplify the
radical expression, if possible (no calculators
needed).
a) c = 6,a = 3,b =
b) c = 12,a = 6,b =
c) c = 10,a = 5,b =
d) c = 16,a = 8,b =
e) a = 2,b = 2,c =
Upcoming
Due today
6:00 PM – Pra
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6:00 PM – Pra
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• O 3:20
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