7. Let y(x) = Enzo anxn be a solution of y" + xy' + y = 0. If the recurrence relation is given by (n + 2)an+2+ an = 0 n ≥ 0, then the general solution can be written as y(x) = ...] X (a) ao [1 - ² + (b) (c) (d) ao [1 - ao [1+ ao [1- - (e) ao [x- x² x² x² 2 + I + 100 000 100 100 100 + 8 x4 X² 8 24 - 8 - - x5 15 ... + a₁ [x - 5/5 + 1/5 x³ x5 3 x5 15 x5 x7 ...] + a₁ [x - ² + - -+ 3 ...] + a₁ [x - ...] + a₁ [2³- ...] + a₁ [1 1 - 12/30 3 15 x5 + 3 15 ...] ...] - ...]
7. Let y(x) = Enzo anxn be a solution of y" + xy' + y = 0. If the recurrence relation is given by (n + 2)an+2+ an = 0 n ≥ 0, then the general solution can be written as y(x) = ...] X (a) ao [1 - ² + (b) (c) (d) ao [1 - ao [1+ ao [1- - (e) ao [x- x² x² x² 2 + I + 100 000 100 100 100 + 8 x4 X² 8 24 - 8 - - x5 15 ... + a₁ [x - 5/5 + 1/5 x³ x5 3 x5 15 x5 x7 ...] + a₁ [x - ² + - -+ 3 ...] + a₁ [x - ...] + a₁ [2³- ...] + a₁ [1 1 - 12/30 3 15 x5 + 3 15 ...] ...] - ...]
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Q7. Let y(x) = Enzo anan be a solution of y" + xy' + y = 0.
If the recurrence relation is given by
(n + 2) an+2+ an = 0
n ≥ 0,
then the general solution can be written as y(x) =
(a) ao [1-2/+
(b)
ao [1-
(c) ao [1+
(d) ao [1-
(e) ao [x
T
NANAA NE A/8
x²
x²
+
8
T
$100 100 100 100
+
+
-
24
T
...] + a₁ [x -
-
-
x³
x5
+
3 15
x3 x5
-+-...]
15
-...] + a₁ [x -
...] + a₁ [x³
...] + a₁ [1-
-
T
...] + a₁ [x -
x³
+
x5
co/8
15
x5 x7
+
3 15
x³ x5
-
+
15
-
...]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6786f013-643c-4548-9b80-003a487634b7%2F13d02f5e-5669-440f-b0f5-5ae28c9075df%2Fk8v5okq_processed.png&w=3840&q=75)
Transcribed Image Text:Q7. Let y(x) = Enzo anan be a solution of y" + xy' + y = 0.
If the recurrence relation is given by
(n + 2) an+2+ an = 0
n ≥ 0,
then the general solution can be written as y(x) =
(a) ao [1-2/+
(b)
ao [1-
(c) ao [1+
(d) ao [1-
(e) ao [x
T
NANAA NE A/8
x²
x²
+
8
T
$100 100 100 100
+
+
-
24
T
...] + a₁ [x -
-
-
x³
x5
+
3 15
x3 x5
-+-...]
15
-...] + a₁ [x -
...] + a₁ [x³
...] + a₁ [1-
-
T
...] + a₁ [x -
x³
+
x5
co/8
15
x5 x7
+
3 15
x³ x5
-
+
15
-
...]
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