**Exercise 7:****Objective:** Label all the C=C double bonds as Z/E in the following compounds. If there is no Z/E isomer, mark as "no isomer."**Structures:**1. **Compound 1:** - A cyclohexene derivative: - There are three substituents: two methyl groups (Me) and one hydrogen (H). - The methyl groups are on opposite sides of the ring, suggesting this may be examined for E/Z configuration.2. **Compound 2:** - An alkene with methyl (Me) and chlorine (Cl) substituents: - Contains two terminal hydrogens (H). - The configuration around the double bond needs to be assessed for isomerism.3. **Compound 3:** - An alkene with three hydrogen (H) atoms and one chlorine (Cl): - The linear arrangement features a C=C double bond, possibly allowing for E/Z evaluation.4. **Compound 4:** - A cyclodecene structure: - Cycloalkene with no substituents protruding, likely indicating no E/Z isomerism due to symmetrical nature.5. **Compound 5:** - A cyclopentenediol derivative featuring bromo (Br) and boronic acid (BO₂H₂) groups: - This compound has substituents on a cyclic double bond with potential E/Z isomerism.6. **Compound 6:** - Includes a C=C bond with fluorine (F), chlorine (Cl), and bromine (Br): - The substituents around the double bond allow evaluation for Z/E isomerism. **Instructions for Educational Use:**- Analyze each structure for possible geometric isomerism around the C=C bond.- Apply the Cahn-Ingold-Prelog priority rules to determine if the highest priority substituents are on the same side (Z) or opposite sides (E) of the double bond.- Note cases where there are no stereochemically distinct substituents resulting in "no isomer."

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Answered: 7. is no Z/E isomer, mark as no…

7. is no Z/E isomer, mark as no isomer). Label all the C=C double bonds as Z/E in the following compounds (if there Me Ме H Н. Ме H H Me H. Br CI F. Br НО B'

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Exercise 7:**

**Objective:** Label all the C=C double bonds as Z/E in the following compounds. If there is no Z/E isomer, mark as "no isomer."

**Structures:**

1. **Compound 1:**
- A cyclohexene derivative:
- There are three substituents: two methyl groups (Me) and one hydrogen (H).
- The methyl groups are on opposite sides of the ring, suggesting this may be examined for E/Z configuration.

2. **Compound 2:**
- An alkene with methyl (Me) and chlorine (Cl) substituents:
- Contains two terminal hydrogens (H).
- The configuration around the double bond needs to be assessed for isomerism.

3. **Compound 3:**
- An alkene with three hydrogen (H) atoms and one chlorine (Cl):
- The linear arrangement features a C=C double bond, possibly allowing for E/Z evaluation.

4. **Compound 4:**
- A cyclodecene structure:
- Cycloalkene with no substituents protruding, likely indicating no E/Z isomerism due to symmetrical nature.

5. **Compound 5:**
- A cyclopentenediol derivative featuring bromo (Br) and boronic acid (BO₂H₂) groups:
- This compound has substituents on a cyclic double bond with potential E/Z isomerism.

6. **Compound 6:**
- Includes a C=C bond with fluorine (F), chlorine (Cl), and bromine (Br):
- The substituents around the double bond allow evaluation for Z/E isomerism.

**Instructions for Educational Use:**

- Analyze each structure for possible geometric isomerism around the C=C bond.
- Apply the Cahn-Ingold-Prelog priority rules to determine if the highest priority substituents are on the same side (Z) or opposite sides (E) of the double bond.
- Note cases where there are no stereochemically distinct substituents resulting in "no isomer."

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