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7. Insert the contents of the hash table in the boxes below given the following conditions: The size of the hash table is 12. Double hashing is used to resolve collisions. The hash function used is H(k)= k mod 12 The second hash function is: H₂(k)=7-(k % 7) What values will be in the hash table after the following sequence of insertions? Insert the values in the boxes below, and show your work for partial credit. 33, 10, 9, 13, 12, 45, 26, 17

7. Insert the contents of the hash table in the boxes below given the following conditions: The size of the hash table is 12. Double hashing is used to resolve collisions. The hash function used is H(k)= k mod 12 The second hash function is: H₂(k)=7-(k % 7) What values will be in the hash table after the following sequence of insertions? Insert the values in the boxes below, and show your work for partial credit. 33, 10, 9, 13, 12, 45, 26, 17

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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7. Insert the contents of the hash table in the boxes below given the following conditions: The size of the hash table is 12. Double hashing is used to resolve collisions. The hash function used is H(k)= k mod 12 The second hash function is: H₂(k)=7-(k % 7) What values will be in the hash table after the following sequence of insertions? Insert the values in the boxes below, and show your work for partial credit. 33, 10, 9, 13, 12, 45, 26, 17 0 1 2 3 4 5 6 7 8 9 10 11
Transcribed Image Text:7. Insert the contents of the hash table in the boxes below given the following conditions: The size of the hash table is 12. Double hashing is used to resolve collisions. The hash function used is H(k)= k mod 12 The second hash function is: H₂(k)=7-(k % 7) What values will be in the hash table after the following sequence of insertions? Insert the values in the boxes below, and show your work for partial credit. 33, 10, 9, 13, 12, 45, 26, 17 0 1 2 3 4 5 6 7 8 9 10 11
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