7. Howard's Hamburgers charges $5.00 per hamburger and sells on average 100 hamburgers per day. He finds that for each $0.25 price increase, he sells 10 fewer hamburgers. It costs Howard $2.00 to make each burger. Determine the price per hamburger Howard should charge in order to maximize his profits.
7. Howard's Hamburgers charges $5.00 per hamburger and sells on average 100 hamburgers per day. He finds that for each $0.25 price increase, he sells 10 fewer hamburgers. It costs Howard $2.00 to make each burger. Determine the price per hamburger Howard should charge in order to maximize his profits.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
Question at top my answer at bottom , I have answer as 3.75 the book says it's 4.75 I'm confused could you help grade 10
![7. Howard's Hamburgers charges $5.00 per hamburger and sells on average 100
hamburgers per day. He finds that for each $0.25 price increase, he sells 10 fewer
hamburgers. It costs Howard $2.00 to make each burger. Determine the price per
hamburger Howard should charge in order to maximize his profits.
✓
-20
Profit =
म
(100) (5) = 2b =
7. -
revenue - expenses
(100-010x) (5 +0.25x)
7
-10x = -100
-10
-10
X = 10
5
19
Aos
.. new price should
•25 x = -5
25
be 5 -1.25 3.75
↓
X=-20
725
= -5
e. -5
10+ (-20)
2
R (100-10(-5)) (5+0.25(5))
A
(150) (3.75) 2(158)
562.5 max revenue
X = # of
•25 chcrasse
E dood how
b = # of
burgers
made
increase of
25 ¢
*√
5 0.25=125
increase
pandset you](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5a4bff3-2356-4c9b-8060-cfb87c1997ab%2F3902b606-3e50-4f60-854f-92072cc960b9%2Fi8ijtvy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7. Howard's Hamburgers charges $5.00 per hamburger and sells on average 100
hamburgers per day. He finds that for each $0.25 price increase, he sells 10 fewer
hamburgers. It costs Howard $2.00 to make each burger. Determine the price per
hamburger Howard should charge in order to maximize his profits.
✓
-20
Profit =
म
(100) (5) = 2b =
7. -
revenue - expenses
(100-010x) (5 +0.25x)
7
-10x = -100
-10
-10
X = 10
5
19
Aos
.. new price should
•25 x = -5
25
be 5 -1.25 3.75
↓
X=-20
725
= -5
e. -5
10+ (-20)
2
R (100-10(-5)) (5+0.25(5))
A
(150) (3.75) 2(158)
562.5 max revenue
X = # of
•25 chcrasse
E dood how
b = # of
burgers
made
increase of
25 ¢
*√
5 0.25=125
increase
pandset you
![7. Howard's Hamburgers charges $5.00 per hamburger and sells on average 100
hamburgers per day. He finds that for each $0.25 price increase, he sells 10 fewer
hamburgers. It costs Howard $2.00 to make each burger. Determine the price per
hamburger Howard should charge in order to maximize his profits.
✓
-20
Profit =
म
(100) (5) = 2b =
7. -
revenue - expenses
(100-010x) (5 +0.25x)
7
-10x = -100
-10
-10
X = 10
5
19
Aos
.. new price should
•25 x = -5
25
be 5 -1.25 3.75
↓
X=-20
725
= -5
e. -5
10+ (-20)
2
R (100-10(-5)) (5+0.25(5))
A
(150) (3.75) 2(158)
562.5 max revenue
X = # of
•25 chcrasse
E dood how
b = # of
burgers
made
increase of
25 ¢
*√
5 0.25=125
increase
pandset you](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5a4bff3-2356-4c9b-8060-cfb87c1997ab%2F3902b606-3e50-4f60-854f-92072cc960b9%2Ft1gjas_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7. Howard's Hamburgers charges $5.00 per hamburger and sells on average 100
hamburgers per day. He finds that for each $0.25 price increase, he sells 10 fewer
hamburgers. It costs Howard $2.00 to make each burger. Determine the price per
hamburger Howard should charge in order to maximize his profits.
✓
-20
Profit =
म
(100) (5) = 2b =
7. -
revenue - expenses
(100-010x) (5 +0.25x)
7
-10x = -100
-10
-10
X = 10
5
19
Aos
.. new price should
•25 x = -5
25
be 5 -1.25 3.75
↓
X=-20
725
= -5
e. -5
10+ (-20)
2
R (100-10(-5)) (5+0.25(5))
A
(150) (3.75) 2(158)
562.5 max revenue
X = # of
•25 chcrasse
E dood how
b = # of
burgers
made
increase of
25 ¢
*√
5 0.25=125
increase
pandset you
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