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7. Find the general solution: y(x? + y²)dx + x(3x² – 5y²)dy = 0 a. y³(y² – x²) = cx b. 2y3(у2 — х?) %3 сх с. Зу? (у? — х?) %3 сх d. 4y3(y2 – x²) = cx -

7. Find the general solution: y(x? + y²)dx + x(3x² – 5y²)dy = 0 a. y³(y² – x²) = cx b. 2y3(у2 — х?) %3 сх с. Зу? (у? — х?) %3 сх d. 4y3(y2 – x²) = cx -

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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7. Find the general solution 

7. Find the general solution: y(x? + y²)dx + x(3x² – 5y²)dy = 0 a. y³(y² – x²) = cx b. 2y3(у2 — х?) %3 сх с. Зу? (у? — х?) %3 сх d. 4y3(y2 — х?) %3 сх -
Transcribed Image Text:7. Find the general solution: y(x? + y²)dx + x(3x² – 5y²)dy = 0 a. y³(y² – x²) = cx b. 2y3(у2 — х?) %3 сх с. Зу? (у? — х?) %3 сх d. 4y3(y2 — х?) %3 сх -
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