7. Find the Area of the regular Pentagon(5-gon) with a radius = 10 inches. Round your final answer to 2 decimal places, Cantral 4 = n-5 Area =

Elementary Geometry For College Students, 7e
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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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Find the Area of the regular Pentagon(5-gon) with a radius = 10 inches. Round your final answer to 2decimal places.

### Problem 7: Area Calculation of a Regular Pentagon

**Question:**
Find the Area of the regular Pentagons (5-gon) with a radius \( r = 10 \) inches. Round your final answer to 2 decimal places.

---

**Diagram Explanation:**

- The image features a regular pentagon (a 5-sided polygon) with a highlighted radius extending from the center to one of the vertices. 
- Within the pentagon, a right triangle is formed by dividing one of the triangular segments of the pentagon, indicating the height (or apothem) of the pentagon.

---

**Variables:**
- **Central Angle (\( \theta \)):**
    The central angle of each triangular segment of the pentagon can be calculated as:
    \[
    \theta = \frac{360^\circ}{n} = \frac{360^\circ}{5} = 72^\circ
    \]

- **Number of sides (\( n \)):**
    \[
    n = 5
    \]

- **Side Length (\( s \)):**
    The side length \( s \) can be calculated from the radius \( r \), using the sine function of half the central angle:
    \[
    s = 2 \times r \times \sin\left(\frac{\theta}{2}\right) = 2 \times 10 \times \sin(36^\circ) \approx 11.76 \text{ inches}
    \]

- **Apothem (\( a \)):**
    The apothem of the pentagon can be calculated using the cosine function of half the central angle:
    \[
    a = r \times \cos\left(\frac{\theta}{2}\right) = 10 \times \cos(36^\circ) \approx 8.09 \text{ inches}
    \]

- **Area Calculation:**
    The area \( A \) of a regular polygon can be calculated using the formula:
    \[
    A = \frac{1}{2} \times n \times s \times a
    \]
    Plugging in the values:
    \[
    A = \frac{1}{2} \times 5 \times 11.76 \times 8.09 \approx 237.76 \text{ square inches}
    \]

---

**Answer:**
The area of
Transcribed Image Text:### Problem 7: Area Calculation of a Regular Pentagon **Question:** Find the Area of the regular Pentagons (5-gon) with a radius \( r = 10 \) inches. Round your final answer to 2 decimal places. --- **Diagram Explanation:** - The image features a regular pentagon (a 5-sided polygon) with a highlighted radius extending from the center to one of the vertices. - Within the pentagon, a right triangle is formed by dividing one of the triangular segments of the pentagon, indicating the height (or apothem) of the pentagon. --- **Variables:** - **Central Angle (\( \theta \)):** The central angle of each triangular segment of the pentagon can be calculated as: \[ \theta = \frac{360^\circ}{n} = \frac{360^\circ}{5} = 72^\circ \] - **Number of sides (\( n \)):** \[ n = 5 \] - **Side Length (\( s \)):** The side length \( s \) can be calculated from the radius \( r \), using the sine function of half the central angle: \[ s = 2 \times r \times \sin\left(\frac{\theta}{2}\right) = 2 \times 10 \times \sin(36^\circ) \approx 11.76 \text{ inches} \] - **Apothem (\( a \)):** The apothem of the pentagon can be calculated using the cosine function of half the central angle: \[ a = r \times \cos\left(\frac{\theta}{2}\right) = 10 \times \cos(36^\circ) \approx 8.09 \text{ inches} \] - **Area Calculation:** The area \( A \) of a regular polygon can be calculated using the formula: \[ A = \frac{1}{2} \times n \times s \times a \] Plugging in the values: \[ A = \frac{1}{2} \times 5 \times 11.76 \times 8.09 \approx 237.76 \text{ square inches} \] --- **Answer:** The area of
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