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7. Evaluate * (D5 - 3D4 + 8D³ + 16D² - 9D - 13)y = 0 y = (C₁ + C₂x)e¯x + С3ex +C4e²x cos3x + C5e²x sin3x y = C₁e* + C₂е¯* + С3e* +C4e²x cos3x +C5e²x sin3x OA) B) y = (C₁ + C₂x + С3x²)ex +C4e²x cos3x +C5e²x sin3x y = (C₁ + C₂ + С3)е¯* +C4e²x cos3x +C5e²x sin3x OD) Upload a clear picture of your solution #7, enclose your final answer.

7. Evaluate * (D5 - 3D4 + 8D³ + 16D² - 9D - 13)y = 0 y = (C₁ + C₂x)e¯x + С3ex +C4e²x cos3x + C5e²x sin3x y = C₁e* + C₂е¯* + С3e* +C4e²x cos3x +C5e²x sin3x OA) B) y = (C₁ + C₂x + С3x²)ex +C4e²x cos3x +C5e²x sin3x y = (C₁ + C₂ + С3)е¯* +C4e²x cos3x +C5e²x sin3x OD) Upload a clear picture of your solution #7, enclose your final answer.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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7. Evaluate * (D5 − 3D¹ + 8D³ + 16D² – 9D – 13)y = 0 y = (C₁+C₂x)e¯x + С3ex +C4e²x cos3x +C5e²x sin3x y = C₁еx + C₂е¯x + С3e* +C4e²x cos3x +C5e²x sin3x OA) OB) y = (C₁ + C₂x + C 3 x ²)e=x +C4e²x cos3x +C5e²x sin3x y = (C₁ + C₂ + С3) ex +C4e²x cos3x +C5e²x sin3x D) Upload a clear picture of your solution #7, enclose your final answer.
Transcribed Image Text:7. Evaluate * (D5 − 3D¹ + 8D³ + 16D² – 9D – 13)y = 0 y = (C₁+C₂x)e¯x + С3ex +C4e²x cos3x +C5e²x sin3x y = C₁еx + C₂е¯x + С3e* +C4e²x cos3x +C5e²x sin3x OA) OB) y = (C₁ + C₂x + C 3 x ²)e=x +C4e²x cos3x +C5e²x sin3x y = (C₁ + C₂ + С3) ex +C4e²x cos3x +C5e²x sin3x D) Upload a clear picture of your solution #7, enclose your final answer.
8. Transform * = e√√²t sin√√2t y=e\ √2 (s − √√2)² + √2 - O A) √2 (s -√2)² + 2 √2 (s + 2)² +2 B) 2 (s − √2)² + 2 D)
Transcribed Image Text:8. Transform * = e√√²t sin√√2t y=e\ √2 (s − √√2)² + √2 - O A) √2 (s -√2)² + 2 √2 (s + 2)² +2 B) 2 (s − √2)² + 2 D)
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