7. Describe a method that can be used to separate each of the following mixtures of metal ions:a. Ag⁺, Pb²⁺b. Mn²⁺, Fe³⁺c. Ni²⁺, Al³⁺d. Cu²⁺, Ni²⁺(Note: The text after "mixtures of metal ions:" is shown as a list of pairs of metal ions with superscript charges.)

The given cations are present under the following categories of major groups according to the solubilities of their compounds: Group I: Ag+, Pb2+Group II: Cu2+Group I: Fe3+, Al3+, Ni2+, Mn2+Ag+ and Pb2+ are Group I cations which can be separated using the following procedure: Add a few drops of hot distilled water and heat the mixture in a hot water bath for some time till the precipitation is complete. Separate the supernatant from the precipitate using centrifugation. The precipitate will contain Ag+ while the supernatant contains Pb2+, which is confirmed by the addition of K2CrO4 and HOAc resulting in the formation of the yellow-orange precipitate of PbCrO4.Mn2+ and Fe3+ belongs to the Group III cations. They can be separated using the following procedure: Add a solution of NH4Cl and NH4OH to the mixture of cations. A brown precipitate formed indicates the presence of Fe(OH)3 or Fe3+ ions while the supernatant consists of Mn2+. To confirm the presence of Mn2+ ions in the supernatant add H2S in basic medium, the formation of pink precipitate indicates the presence of MnS or Mn2+ cations.Ni2+ and Al3+ belongs to the Group III cations. They can be separated using the following procedure: Add a solution of NH4Cl and NH4OH to the mixture of cations. A white precipitate formed indicates the presence of Al(OH)3 or Al3+ ions while the supernatant consists of Ni2+. To confirm the presence of Ni2+ ions in the supernatant add H2S in basic medium, the formation of black precipitate indicates the presence of NiS or Ni2+ cations.Cu2+ belongs to the Group 2 cations while Ni2+ belongs to the Group III cations. They can be separated using the following procedure: Add H2S in acidic medium. The formation of black precipitate indicates the presence of CuS or Cu2+ ions while the solution will consist of Ni2+ ions.