7. Consider the following IVP with discontinuous right hand side. (1 x < 1 0 x ≥1 (c) y = (d) y = y" + 2y + y = The complementary solution to this equation is y₁ = C₁е¯ + c₂xe. Solve this IVP. (a) y = e-+ xe¬ª (b) y=1+xe= (e) y = 1+re x < 1 -² + xе-² x>1 1+re-r x < 1 re-*+re-2+1 x>1 3 e-² + xе-² x < 1 1+re=¹ x>1 y(0) = 1, y'(0) = 1.
7. Consider the following IVP with discontinuous right hand side. (1 x < 1 0 x ≥1 (c) y = (d) y = y" + 2y + y = The complementary solution to this equation is y₁ = C₁е¯ + c₂xe. Solve this IVP. (a) y = e-+ xe¬ª (b) y=1+xe= (e) y = 1+re x < 1 -² + xе-² x>1 1+re-r x < 1 re-*+re-2+1 x>1 3 e-² + xе-² x < 1 1+re=¹ x>1 y(0) = 1, y'(0) = 1.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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