### Problem 7**Charge Distribution on an Insulating Sphere**Charge \( Q = 4\mu C \) is distributed uniformly over the volume of an insulating sphere that has radius \( R = 5cm \).#### (a) Potential DifferenceThe potential difference between the center of the sphere and the surface of the sphere is given by:\[V_0 - V_R = \int_0^R E dr = \int_0^R \frac{Q}{4\pi\varepsilon_0 R^3} r dr = \frac{Q}{8\pi\varepsilon_0 R} = 359672V = 359.672kV \quad (\text{True, False})\]#### (b) Self EnergyThe self energy of the sphere is calculated as follows:\[U = \frac{3}{5} \frac{Q^2}{4\pi\varepsilon_0 R} = 1.726J \quad (\text{True, False})\]### Explanation of Formulas- **Potential Difference**: This evaluates the work done in moving a charge from the center to the surface of the sphere. The integral calculates the electric field's contribution over the radius of the sphere. - **Self Energy**: This energy represents the energy required to assemble the sphere by bringing small charges from infinity to form the complete sphere.### NoteEnsure to verify whether the given values and calculations are marked as true or false in practice exercises or exams.

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Answered: 7. Charge Q = 4µC is distributed…

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