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7. Call the four players A, B, C, and D. The number of ways of choosing the positions in the deck that 52 will be occupied by the four aces is 4 Since player A will receive 13 cards, the number of ways of choosing the positions in the deck for the four aces so that all of them will be received by player 13 A is 4. Similarly, since player B will receive 13 other cards, the number of ways of choosing the positions for the four aces so that all of them will be received by player B is A similar result is true for each of the other players. Therefore, the total number of ways of choosing the positions in the deck for the four aces so that all of them will be received by the same player is 4 . Thus, the final probability is

7. Call the four players A, B, C, and D. The number of ways of choosing the positions in the deck that 52 will be occupied by the four aces is 4 Since player A will receive 13 cards, the number of ways of choosing the positions in the deck for the four aces so that all of them will be received by player 13 A is 4. Similarly, since player B will receive 13 other cards, the number of ways of choosing the positions for the four aces so that all of them will be received by player B is A similar result is true for each of the other players. Therefore, the total number of ways of choosing the positions in the deck for the four aces so that all of them will be received by the same player is 4 . Thus, the final probability is

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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17. Call the four players A, B, C, and D. The number of ways of choosing the positions in the deck that 52 Since player A will receive 13 cards, the number of ways 4 will be occupied by the four aces is of choosing the positions in the deck for the four aces so that all of them will be received by player A is Similarly, since player B will receive 13 other cards, the number of ways of choosing the positions for the four aces so that all of them will be received by player B is A similar result is true for each of the other players. Therefore, the total number of ways of choosing the positions in the deck for the four aces so that all of them will be received by the same player is 4 Thus, the final probability is
Transcribed Image Text:17. Call the four players A, B, C, and D. The number of ways of choosing the positions in the deck that 52 Since player A will receive 13 cards, the number of ways 4 will be occupied by the four aces is of choosing the positions in the deck for the four aces so that all of them will be received by player A is Similarly, since player B will receive 13 other cards, the number of ways of choosing the positions for the four aces so that all of them will be received by player B is A similar result is true for each of the other players. Therefore, the total number of ways of choosing the positions in the deck for the four aces so that all of them will be received by the same player is 4 Thus, the final probability is
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