7. Calculate the molarity of an acetic acid solution if 34.57 mL of this solution are needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide CH3COOH (aq) + NaOH (aq) Na*(aq) + CH3COOH"(aq) + H20 (1)
7. Calculate the molarity of an acetic acid solution if 34.57 mL of this solution are needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide CH3COOH (aq) + NaOH (aq) Na*(aq) + CH3COOH"(aq) + H20 (1)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 7:** Calculate the molarity of an acetic acid solution if 34.57 mL of this solution is needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide.
**Chemical Equation:**
\[ \text{CH}_3\text{COOH (aq)} + \text{NaOH (aq)} \rightarrow \text{Na}^+ \text{(aq)} + \text{CH}_3\text{COO}^- \text{(aq)} + \text{H}_2\text{O (l)} \]
**Explanation:**
The equation shows the reaction between acetic acid (CH₃COOH) and sodium hydroxide (NaOH), producing sodium ions (Na⁺), acetate ions (CH₃COO⁻), and water (H₂O). To find the molarity of the acetic acid solution, use the stoichiometry of the reaction and the known concentration of NaOH.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d353b8f-29b7-4b65-b20b-402aa69a76cb%2F41e535ec-d62f-4370-b711-83338520a498%2Fwsib3y7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 7:** Calculate the molarity of an acetic acid solution if 34.57 mL of this solution is needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide.
**Chemical Equation:**
\[ \text{CH}_3\text{COOH (aq)} + \text{NaOH (aq)} \rightarrow \text{Na}^+ \text{(aq)} + \text{CH}_3\text{COO}^- \text{(aq)} + \text{H}_2\text{O (l)} \]
**Explanation:**
The equation shows the reaction between acetic acid (CH₃COOH) and sodium hydroxide (NaOH), producing sodium ions (Na⁺), acetate ions (CH₃COO⁻), and water (H₂O). To find the molarity of the acetic acid solution, use the stoichiometry of the reaction and the known concentration of NaOH.
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