**Question 7:** Calculate the molarity of an acetic acid solution if 34.57 mL of this solution is needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide.**Chemical Equation:**\[ \text{CH}_3\text{COOH (aq)} + \text{NaOH (aq)} \rightarrow \text{Na}^+ \text{(aq)} + \text{CH}_3\text{COO}^- \text{(aq)} + \text{H}_2\text{O (l)} \]**Explanation:**The equation shows the reaction between acetic acid (CH₃COOH) and sodium hydroxide (NaOH), producing sodium ions (Na⁺), acetate ions (CH₃COO⁻), and water (H₂O). To find the molarity of the acetic acid solution, use the stoichiometry of the reaction and the known concentration of NaOH.

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7. Calculate the molarity of an acetic acid solution if 34.57 mL of this solution are needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide CH3COOH (aq) + NaOH (aq) Na*(aq) + CH3COOH"(aq) + H20 (1)

7. Calculate the molarity of an acetic acid solution if 34.57 mL of this solution are needed to neutralize 25.19 mL of 0.1025 M sodium hydroxide CH3COOH (aq) + NaOH (aq) Na*(aq) + CH3COOH"(aq) + H20 (1)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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